Gebäude Suchabfrage in laravel5 gibt Fehler Syntaxfehler oder Zugriffsverletzung: 1064

Question

Ich möchte eine einfache Suchfunktion in laravel5 App als

use DB; 
use App\Models\User; 
use Illuminate\Http\Request; 

use ConnectIn\Http\Requests; 

class SearchController extends Controller 
{ 
    public function getResults(Request $request) 
    { 

     $query = $request->input('name'); 
     if (!$query) { 
      return redirect()-> route('home') -> with('info', "Search must contain some charactres"); 
     } 
     else{ 

     $users = User::where(DB::raw("CONCAT (first_name, ' ', last_name), "), 
     "LIKE", "%{$query}%") 
    ->orwhere('username', "LIKE", "%{$query}%") 
    ->get(); 
    dd('search is ALL OK' . $users); 
    } 
     return view('search.results'); 
    } 

} 

mit dem Code oben Ich bekomme Fehler

QueryException in Connection.php line 673: 
SQLSTATE[42000]: Syntax error or access violation: 1064 You have an error in your SQL syntax; check the manual that corresponds to your MariaDB server version for the right syntax to use near ' LIKE ? or `username` LIKE ?' at line 1 (SQL: select * from `users` where CONCAT (fisrt_name, ' ', last_name), LIKE %s% or `username` LIKE %s%) 
    in Connection.php line 673 
    at Connection->runQueryCallback('select * from `users` where CONCAT (fisrt_name, ' ', last_name), LIKE ? or `username` LIKE ?', array('%{$query}%', '%{$query}%'), object(Closure)) in Connection.php line 629 
    at Connection->run('select * from `users` where CONCAT (fisrt_name, ' ', last_name), LIKE ? or `username` LIKE ?', array('%{$query}%', '%{$query}%'), object(Closure)) in Connection.php line 342 
    at Connection->select('select * from `users` where CONCAT (fisrt_name, ' ', last_name), LIKE ? or `username` LIKE ?', array('%{$query}%', '%{$query}%'), true) in Builder.php line 1508 
    at Builder->runSelect() in Builder.php line 1494 
    at Builder->get(array('*')) in Builder.php line 596 
    at Builder->getModels(array('*')) in Builder.php line 303 
    at Builder->get() in SearchController.php line 25 
    at SearchController->getResults(object(Request)) 
    at call_user_func_array(array(object(SearchController), 'getResults'), array(object(Request))) in Controller.php line 80 
    at Controller->callAction('getResults', array(object(Request))) in ControllerDispatcher.php line 146 
    at ControllerDispatcher->call(object(SearchController), object(Route), 'getResults') in ControllerDispatcher.php line 94 
    at ControllerDispatcher->Illuminate\Routing\{closure}(object(Request)) 
    at call_user_func(object(Closure), object(Request)) in Pipeline.php line 52 
    at Pipeline->Illuminate\Routing\{closure}(object(Request)) 
    at call_user_func(object(Closure), object(Request)) in Pipeline.php line 103 
    at Pipeline->then(object(Closure)) in ControllerDispatcher.php line 96 
    at ControllerDispatcher->callWithinStack(object(SearchController), object(Route), object(Request), 'getResults') in ControllerDispatcher.php line 54 

Answer 1

Prüfen Sie zuerst $ query enthalten die Zeichenfolge

User::where(DB::raw('CONCAT(first_name," ", last_name)'), 'like', '%'.$query.'%')->orwhere('username', 'like', '%'.$query.'%')->get(); 

Answer 2

vorgesehen umzusetzen

Ihre Abfrage hat einen Syntaxfehler und einen Tippfehler.

CONCAT (fisrt_name, ' ', last_name), LIKE %s% 

Sollte sein:

CONCAT (first_name, ' ', last_name) LIKE %s% 

Sie können auch tun:

SELECT * FROM `users` 
CONCAT (first_name, ' ', last_name) AS fullname 
WHERE `username` LIKE %s% 
HAVING fullname LIKE %s%