Fehlermeldung am Anfang des Formulars anzeigen

Question

Ich versuche, den folgenden Fehler zu zeigen, wenn einige einmal die Übergabeschaltfläche gedrückt und das erforderliche Feld/s nicht ausgefüllt hat.

Answer 1

<?php 
require_once("includes/database.php"); 
require_once("includes/functions.php"); 

if(isset($_POST['full_name'])) { 
    $required = array('full_name','user_name','email','pwd','pwd2'); 
    $missing = array(); 
    $validation = array(
     'full_name' => 'Please provide your full name', 
     'user_name' => 'Please provide your username', 
     'email'  => 'Please provide your valid email address', 
     'pwd'  => 'Please provide your password', 
     'pwd2'  => 'Please confirm your password', 
     'userdup' => 'Username already registered', 
     'emaildup'  => 'Email address already registered', 
     'mismatch'  => 'Passwords do not match' 
    ); 

    //Sanitise and clean function 
    $full_name = escape($_POST['full_name']); 
    $user_name = escape($_POST['user_name']); 
    $email = escape($_POST['email']); 
    $pwd = escape($_POST['pwd']); 
    $pwd2 = escape($_POST['pwd2']); 

    foreach($_POST as $key => $value) { 
     $value = trim($value); 
     if(empty($value) && in_array($key,$required)) { 
      array_push($missing,$key); 
     } else { 
      ${$key} = escape($value); //Why exacly do you need to have extra stuff? 
     } 
    } 
    //iterate over the missing elements, and display them 
    foreach ($missing as $m){ 
     echo echo "<strong>Error: </strong>: " . $validation[$m] . "<br>"; 
    } 
    //You need to do some more stuffs, like query the DB to check if the username is a duplicate or not. 
} 
//...rest of your code ..