string hex to pointer get value

Question

Von der Konsole aus frage ich nach einer hexadezimalen Zeichenfolge, die in einen Zeiger konvertiert werden soll, um auf ein Element im Speicher zu verweisen.

#include <iostream> 
#include <sstream> 
#include <Windows.h> 

int char_to_pointer(std::string input); 

int main() { 
    int sample = 100; // lets say this address is 0xc1f1 
    std::string input_; 
    std::cout << "addr:" << &sample << std::endl; 
    std::cout << "what is the memory address?:" << std::endl; 
    std::cin >> input_; 

    unsigned int inp = char_to_pointer(input_); 
    std::cout << "imp: " << inp << std::endl; 

    Sleep(10000); 

    return 0; 
} 

int char_to_pointer(std::string input) { 
    return std::stoul(input, nullptr, 16); 
} 

Mein Problem ist, dass char_to_pointer nur den Hex-String in eine Dezimalzahl umwandelt.

das ist, was ich will:

input: "0xc1f1" 
output: 100 

Answer 1

fand ich die Lösung:

#include <iostream> 
#include <sstream> 
#include <Windows.h> 
#include <string> 

int *char_to_pointer(std::string input); 

int main() { 
    int sample = 100; // lets say this address is 0xc1f1 
    std::string input_; 
    std::cout << "addr:" << &sample << std::endl; 
    std::cout << "what is the memory address?:" << std::endl; 
    std::cin >> input_; 

    int *inp = char_to_pointer(input_); 
    std::cout << "imp: " << inp << std::endl; 
    std::cout << "imp*: " << *inp << std::endl;//This was my solution 
    std::cout << "imp&: " << &inp << std::endl; 

    Sleep(10000); 

    return 0; 
} 

int *char_to_pointer(std::string input) { 
    return (int *)std::stoul(input, nullptr, 16); 
}