flask-mail TypeError: getaddrinfo() argument 1 muss string sein oder None

Question

Ich möchte flash mail in meiner webapp verwenden und bekomme einen Fehler, den ich nicht wirklich verstehe. Befolgen Sie die Richtlinien und es kann nicht funktionieren. Im folgenden Prozess möchte ich App an einen neuen registrierten Benutzer senden.

Config:

MAIL_SERVER='smtp.gmail.com', 
MAIL_PORT=465, 
MAIL_USE_SSL=True, 
MAIL_USE_TLS=False, 
MAIL_USERNAME = 'myMail@gmail.com', 
MAIL_PASSWORD = '******' 

Ausblick:

from flask_mail import Mail, Message 
mail = Mail(app) 


@app.route("/send_mail/") 
def send_mail(): 
    msg = Message('Hello', sender = 'myMail@gmail.com', recipients = ['somebody@gmail.com']) 
    msg.body = "This is the email body" 
    mail.send(msg) 

Fehler Ich erhalte:

File "C:\venvs\test\lib\site-packages\flask\app.py", line 1994, in __call__ 
return self.wsgi_app(environ, start_response) 
File "C:\venvs\test\lib\site-packages\flask\app.py", line 1985, in wsgi_app 
response = self.handle_exception(e) 
File "C:\venvs\test\lib\site-packages\flask\app.py", line 1540, in handle_exception 
reraise(exc_type, exc_value, tb) 
File "C:\venvs\test\lib\site-packages\flask\_compat.py", line 33, in reraise 
raise value 
File "C:\venvs\test\lib\site-packages\flask\app.py", line 1982, in wsgi_app 
response = self.full_dispatch_request() 
File "C:\venvs\test\lib\site-packages\flask\app.py", line 1614, in full_dispatch_request 
rv = self.handle_user_exception(e) 
File "C:\venvs\test\lib\site-packages\flask\app.py", line 1517, in handle_user_exception 
reraise(exc_type, exc_value, tb) 
File "C:\venvs\test\lib\site-packages\flask\_compat.py", line 33, in reraise 
raise value 
File "C:\venvs\test\lib\site-packages\flask\app.py", line 1612, in full_dispatch_request 
rv = self.dispatch_request() 
File "C:\venvs\test\lib\site-packages\flask\app.py", line 1598, in dispatch_request 
return self.view_functions[rule.endpoint](**req.view_args) 
File "C:\venvs\test\views.py", line 202, in send_mail 
mail.send(msg) 
File "C:\venvs\test\lib\site-packages\flask_mail.py", line 491, in send 
with self.connect() as connection: 
File "C:\venvs\test\lib\site-packages\flask_mail.py", line 144, in __enter__ 
self.host = self.configure_host() 
File "C:\venvs\test\lib\site-packages\flask_mail.py", line 156, in configure_host 
host = smtplib.SMTP_SSL(self.mail.server, self.mail.port) 
File "C:\Python\lib\smtplib.py", line 1029, in __init__ 
source_address) 
File "C:\Python\lib\smtplib.py", line 251, in __init__ 
(code, msg) = self.connect(host, port) 
File "C:\Python\lib\smtplib.py", line 335, in connect 
self.sock = self._get_socket(host, port, self.timeout) 
File "C:\Python\lib\smtplib.py", line 1035, in _get_socket 
self.source_address) 
File "C:\Python\lib\socket.py", line 704, in create_connection 
for res in getaddrinfo(host, port, 0, SOCK_STREAM): 
File "C:\Python\lib\socket.py", line 743, in getaddrinfo 
for res in _socket.getaddrinfo(host, port, family, type, proto, flags): 
TypeError: getaddrinfo() argument 1 must be string or None 

Irgendwelche Ideen?

Answer 1

Ihre Einstellungen in Ihrer Konfig Datei scheinen ein nachkommendes Komma zu haben, was sie zu Tupeln machen würde. Flask-Mail beschwert sich, dass der an getaddrinfo übergebene Wert host kein String ist - es ist höchstwahrscheinlich ein Tupel.

Das Entfernen der abschließenden Kommas kann dieses Problem beheben.