2016-07-13 14 views
0

Ich möchte alle Daten und Namen von Tagen eines bestimmten Monats eines Jahres in PHP drucken. Ich versuche, cal_days_in_month Funktion zu verwenden, aber nicht meine gewünschte Funktionalität zu erreichen. Bitte schlage mir den Weg vor.Wie erhalten Sie alle Daten und Namen von Tagen eines bestimmten Monats eines Jahres in PHP?

<?php 
$number_of_days = cal_days_in_month(CAL_GREGORIAN, 7, 2016); 
for ($x = 1; $x <= $number_of_days; $x++) 
{ 
    echo "<p>Day: ".$x."</p>"; 
} 
?> 

Ausgang:

Day: 1 
Day: 2 
... 
... 
Day: 31 

Gibt es eine Möglichkeit, ich kann eine Ausgabe wie diese:

Day: July 1, 2016 (Friday) 
Day: July 2, 2016 (Saturday) 
... 
... 
Day: July 31, 2016 (Sunday) 
+1

Sie könnten 'strtotime();' Es hat eine 1+ Tag-Funktion, die Sie Schleife, etwa wie $ Tag = strtotime ('1. Juli 2016', '+1 Tag'); 'und dann verwenden können 'date (, $ day);' um die Ausgabe wie gewünscht anzuzeigen – Epodax

Antwort

3

Versuchen:

$number_of_days = cal_days_in_month(CAL_GREGORIAN,$month, $year); 
for ($x = 1; $x <= $number_of_days; $x++) { 
    echo date("F", strtotime($x . "-" . $month . "-" . $year)) . " " . $x . "," . $year . "(" . date("l", strtotime($x . "-" . $month . "-" . $year)) . ")<br/>"; 
} 

Ausgabe:

July 1,2016(Friday) 
July 2,2016(Saturday) 
July 3,2016(Sunday) 
July 4,2016(Monday) 
July 5,2016(Tuesday) 
July 6,2016(Wednesday) 
July 7,2016(Thursday) 
July 8,2016(Friday) 
July 9,2016(Saturday) 
July 10,2016(Sunday) 
July 11,2016(Monday) 
July 12,2016(Tuesday) 
July 13,2016(Wednesday) 
July 14,2016(Thursday) 
July 15,2016(Friday) 
July 16,2016(Saturday) 
July 17,2016(Sunday) 
July 18,2016(Monday) 
July 19,2016(Tuesday) 
July 20,2016(Wednesday) 
July 21,2016(Thursday) 
July 22,2016(Friday) 
July 23,2016(Saturday) 
July 24,2016(Sunday) 
July 25,2016(Monday) 
July 26,2016(Tuesday) 
July 27,2016(Wednesday) 
July 28,2016(Thursday) 
July 29,2016(Friday) 
July 30,2016(Saturday) 
July 31,2016(Sunday) 
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