Die folgenden Arbeiten wie erwartet:
SELECT Diff = CASE DATEDIFF(HOUR, StartTime, EndTime)
WHEN 0 THEN CAST(DATEDIFF(MINUTE, StartTime, EndTime) AS VARCHAR(10))
ELSE CAST(60 - DATEPART(MINUTE, StartTime) AS VARCHAR(10)) +
REPLICATE(',60', DATEDIFF(HOUR, StartTime, EndTime) - 1) +
+ ',' + CAST(DATEPART(MINUTE, EndTime) AS VARCHAR(10))
END
FROM (VALUES
(CAST('11:15' AS TIME), CAST('13:15' AS TIME)),
(CAST('10:45' AS TIME), CAST('18:59' AS TIME)),
(CAST('10:45' AS TIME), CAST('11:59' AS TIME))
) t (StartTime, EndTime);
24 Spalten zu erhalten, könnten Sie 24 case-Ausdrücke verwenden, so etwas wie:
SELECT [0] = CASE WHEN DATEDIFF(HOUR, StartTime, EndTime) = 0
THEN DATEDIFF(MINUTE, StartTime, EndTime)
ELSE 60 - DATEPART(MINUTE, StartTime)
END,
[1] = CASE WHEN DATEDIFF(HOUR, StartTime, EndTime) = 1
THEN DATEPART(MINUTE, EndTime)
WHEN DATEDIFF(HOUR, StartTime, EndTime) > 1 THEN 60
END,
[2] = CASE WHEN DATEDIFF(HOUR, StartTime, EndTime) = 2
THEN DATEPART(MINUTE, EndTime)
WHEN DATEDIFF(HOUR, StartTime, EndTime) > 2 THEN 60
END -- ETC
FROM (VALUES
(CAST('11:15' AS TIME), CAST('13:15' AS TIME)),
(CAST('10:45' AS TIME), CAST('18:59' AS TIME)),
(CAST('10:45' AS TIME), CAST('11:59' AS TIME))
) t (StartTime, EndTime);
Im Folgenden auch funktioniert, und kürzere kann am Ende die gleiche als Wiederholung über Case-Ausdruck und über:
WITH Numbers (Number) AS
( SELECT ROW_NUMBER() OVER(ORDER BY t1.N) - 1
FROM (VALUES (1), (1), (1), (1), (1), (1)) AS t1 (N)
CROSS JOIN (VALUES (1), (1), (1), (1)) AS t2 (N)
), YourData AS
( SELECT StartTime, EndTime
FROM (VALUES
(CAST('11:15' AS TIME), CAST('13:15' AS TIME)),
(CAST('09:45' AS TIME), CAST('18:59' AS TIME)),
(CAST('10:45' AS TIME), CAST('11:59' AS TIME))
) AS t (StartTime, EndTime)
), PivotData AS
( SELECT t.StartTime,
t.EndTime,
n.Number,
MinuteDiff = CASE WHEN n.Number = 0 AND DATEDIFF(HOUR, StartTime, EndTime) = 0 THEN DATEDIFF(MINUTE, StartTime, EndTime)
WHEN n.Number = 0 THEN 60 - DATEPART(MINUTE, StartTime)
WHEN DATEDIFF(HOUR, t.StartTime, t.EndTime) <= n.Number THEN DATEPART(MINUTE, EndTime)
ELSE 60
END
FROM YourData AS t
INNER JOIN Numbers AS n
ON n.Number <= DATEDIFF(HOUR, StartTime, EndTime)
)
SELECT *
FROM PivotData AS d
PIVOT
( MAX(MinuteDiff)
FOR Number IN
( [0], [1], [2], [3], [4], [5],
[6], [7], [8], [9], [10], [11],
[12], [13], [14], [15], [16], [17],
[18], [19], [20], [21], [22], [23]
)
) AS pvt;
Es funktioniert, indem auf eine Tabelle von 24 Zahlen verbinden, so dass der Fall Ausdruck nicht wiederholt werden muss, dann diese 24 Zahlen rollte zurück in Spalten mit PIVOT
können Sie bitte die Ausgabe, was Sie wollen? – mohan111
Haben Sie schon etwas probiert? – danish
Ich brauche den Ausgang für die erste Zeile der Daten als 45,60,15. Es ist genug, um die Werte als separate Spalten zu drucken. –