cakephp 3.x Sub wählen Sie einen Zählwert erhalten

Question

nach einigen Recherchen finde ich diese Aussage erstellt, aber es funktioniert nicht wie erwartet:

public $virtualFields = array(
    'count' => "SELECT COUNT(plans_trainings.id) FROM plans_trainings, trainings, projects WHERE plans_trainings.training_id = trainings.id AND projects.location_id = locations.id AND plans_trainings.project_id = projects.id" 
); 

public function trainingsPerLocationChartData(){ 
$this->loadModel('Locations'); 
$locationsDiagramData = $this->Locations->find('all', array(
      'fields' => array(
       'locations.id', 
       'locations.description', 
       'locations.count' /* virtuel field */ 
      ) 
     )); 

Die Erklärung wird wie folgt aussehen:

'sql' => 'SELECT locations.id AS `locations__id`, locations.description AS `locations__description`, locations.count AS `locations__count` FROM locations Locations' 

Das virtuelle Feld wird überhaupt nicht erkannt. Was mache ich falsch?

UPDATE: Ich fand heraus, dass ich es so nennen haben:

'count' => "(SELECT COUNT(plans_trainings.id) FROM plans_trainings, trainings, projects WHERE plans_trainings.training_id = trainings.id AND projects.location_id = locations.id AND plans_trainings.project_id = projects.id) AS `counter`" 

Ich habe() um die Auswahl.

$locationsDiagramData = $this->Locations->find('all') 
      ->select(['locations.id', 'locations.description', $this->virtualFields['count']]); 

Aber ich immer noch eine falsche SQL-Syntax erhalten:

SELECT locations.id AS `locations__id`, locations.description AS `locations__description`, (SELECT COUNT(plans_trainings.id) FROM plans_trainings, trainings, projects WHERE plans_trainings.training_id = trainings.id AND projects.location_id = locations.id AND plans_trainings.project_id = projects.id) AS `counter` AS (SELECT COUNT(plans_trainings__id) FROM plans_trainings, trainings, projects WHERE plans_trainings FROM locations Locations 

das "letzte" Problem scheint nur diesen Teil nach AS counter:

AS (SELECT COUNT (plans_trainings__id) FROM pläne_trainings, trainings, projekte WO plant_trainings

Das ist was die Aussage bricht! Irgendwelche Ideen, um das zu lösen? Wenn ich die Anweisung in phpmyadmin ausführen und diesen erwähnten Teil entfernen, funktioniert die Anweisung gut und bringt die richtigen Ergebnisse!

UPDATE 2: das ist die einfache Erklärung:

select 
       locations.id, 
    locations.description, 
    (
           select 
               count(plans_trainings.id) 
           from 
               plans_trainings, 
      trainings, 
      projects 
           where 
               plans_trainings.training_id = trainings.id 
               and projects.location_id = locations.id 
               and plans_trainings.project_id = projects.id 
    ) as 'Anzahl' 
from 
       locations; 

Answer 1

dies versuchen Controller

$this->loadModel('Locations'); 
$this->loadModel('PlansTrainings'); 
$this->loadModel('Trainings'); 
$this->loadModel('Projects'); 
$sub_query=$this->PlansTrainings->find()->select(['cnt1'=>'count(PlansTrainings.id)'])->join([ 
     [ 
      'table' => 'trainings', 
      'alias' => 'Trainings', 
      'type' => 'INNER', 
      'conditions' => 'PlansTrainings.training_id=Trainings.id', 
     ], 
     [ 
      'table' => 'projects', 
      'alias' => 'Projects', 
      'type' => 'INNER', //LEFT, RIGHT... 
      'conditions' => ['Projects.location_id=PlansTrainings.id','PlansTrainings.project_id=Projects.id'], 
     ], 
]); 
$locationsDiagramData = $this->Locations->find()->select(['id', 'description','count'=>$sub_query]);