PHP und SQL (Versuche, meine Datenbank mit Senden-Schaltfläche zu aktualisieren)

Question

Ich versuche, mein Feedback in meinem SQL-Datenbank-Formular mit Hilfe der Schaltfläche "Senden" zu aktualisieren, aber ich bin nicht dazu in der Lage. Bitte helfen Sie!

if (isset($_POST['submitreport'])) 
      { 
       $dbCon = mysqli_connect("localhost","root","","Hun"); 
       $report = strip_tags($_POST['report']); 

       $sql = "UPDATE Feedback SET report='$report' WHERE username='$username' AND date='$date' "; 

       $query = mysqli_query($dbCon, $sql); 


      } 

Answer 1

<?php 
    if (isset($_POST['submitreport'])) 
    { 
    $dbCon = mysqli_connect("localhost","root","","Hun"); 
    $username = 'test'; 
    $report = strip_tags($_POST['report']); 
    $date = date('m-d-Y'); 

    $sql = "UPDATE Feedback SET report='".$report."' WHERE username='".$username."' AND date='".$date."'"; 

    $query = mysqli_query($dbCon, $sql); 
    } 
    ?> 

Answer 2

<?php 
     if (isset($_POST['submitreport'])) 

    { 
     $monthDayYear = date('m-d-Y'); 

     $dbConnnection = mysqli_connect("localhost","root","","Hun"); 

     $dbUsername = strip_tags($_POST['report']); 

     $sqlQuery = "UPDATE Feedback SET report='".$report."' WHERE username='".$username."' AND date='".$monthDayYear."'"; 

     $queryExecute = mysqli_query($dbConnection, $sqlQuery); 


     } 

    ?>