Beitreten von drei verschiedenen MySQL Abfragen Tabellen

Question

Hai Ich bin neu in PHP und MySQL. Hier möchte ich drei verschiedene Quires verbinden. Hier ist meine Anfragen

Query1:

SELECT u.user_name,u.first_name 
FROM users u join users_cstm uc on u.id=uc.id_c 
WHERE u.deleted=0? 

Query2:

SELECT l.assigned_user_id,count(*) AS lead_count 
FROM lead l GROUP BY l.assigned_user_id? 

Abfrage3:

SELECT l.assigned_user_id,AVG(DATEDIFF(l.date_modified,l.date_entered)) AS avgdays 
FROM leads l GROUP BY l.assigned_user_id? 

und so..on ..

Dies ist Ergebnis, das ich suche für benutzername, vorname, lead_count, avgdays. aus drei Tabellen.

BigQuery join of three tables

Ich habe meine Lösung aus dem obigen Link versucht. Aber ich habe das Ergebnis nicht bekommen?

Vielen Dank für die Hilfe und Anregungen.

Answer 1

Versuchen unter query: -

SELECT u.user_name,u.first_name, 
lead_table.lead_count,lead_table.avgdays 
FROM users u join users_cstm uc on u.id=uc.id_c 
left join 
(SELECT l.assigned_user_id, 
     AVG(l.date_modified) AS avgdays, 
     count(*) AS lead_count 
FROM leads l GROUP BY l.assigned_user_id) lead_table 
on u.id=lead_table.assigned_user_id 
WHERE u.deleted=0; 

Answer 2

Versuchen Sie folgendes:

SELECT id,user_name,first_name,lead_count,avgdays from 
(SELECT id,user_name,first_name,lead_count from 
(SELECT u.id,u.user_name,u.first_name FROM users u,users_cstm uc where u.id=uc.id_c and u.deleted=0) as a 

LEFT JOIN 

(SELECT l.assigned_user_id,count(*) AS lead_count FROM lead l GROUP BY l.assigned_user_id) as b 
on a.id = b.assigned_user_id) as a 

LEFT JOIN 

(SELECT l.assigned_user_id,AVG(DATEDIFF(l.date_modified,l.date_entered)) AS avgdays 
FROM leads l GROUP BY l.assigned_user_id) as b 
on a.id = b.assigned_user_id