Ich habe diese Abfrage, die korrekte Ergebnis für mich zurückgibt.Ausziehen Jahr Spalte und Display Jahr Spalte in der horizontalen Spalte aus der gleichen Abfrage in Postgre Sql
SELECT distinct(companies.name),
date_part('year', scopes.time_stamp) as fy,
count(def.dp_code)as answ_count
FROM companies companies,
scopes scopes,
values dp,
definition def,
content cd
where scopes.company_id = companies.company_id
and scopes.scope_id=dp.scope_id
and dp.content_id=cd.definition_id
and def.definition_id=cd.definition_id
group by companies.name, date_part('year',scopes.time_stamp)
ORDER BY companies.name
Unten ist das Ergebnis der obigen Abfrage.
name fy count
3M Co 2002 200
3M Co 2003 100
3M Co 2004 150
3M Co 2005 160
3M Co 2006 169
AB SKF 2002 212
AB SKF 2003 214
AB SKF 2004 215
AB SKF 2005 237
AB SKF 2006 456
3i Group plc 2002 546
3i Group plc 2003 214
3i Group plc 2004 215
3i Group plc 2005 237
3i Group plc 2006 456
Ich brauche das Ergebnis horizontal wie folgt angezeigt:
name 2002 2003 2004 2005 2006
3M Co 200 100 150 160 169
AB SKF
3i Group plc 546 214 215 237 456
Modified Abfrage, aber ich bin nicht immer die richtige count.I weiß nicht, wie die ans_count.Please mir berechnen hilft dafür.
SELECT
distinct(companies.name),
count(CASE WHEN date_part('year', scopes.time_stamp) = 2002 THEN answ_count end) AS Year1,
count(CASE WHEN date_part('year', scopes.time_stamp) = 2003 THEN answ_count end) AS Year2,
count(CASE WHEN date_part('year', scopes.time_stamp) = 2004 THEN answ_count end) AS Year3,
count(CASE WHEN date_part('year', scopes.time_stamp) = 2005 THEN answ_count end) AS Year4,
count(CASE WHEN date_part('year', scopes.time_stamp) = 2006 THEN answ_count end) AS Year5,
count(CASE WHEN date_part('year',scopes.time_stamp) = 2007 THEN answ_count end) AS Year6,
count(CASE WHEN date_part('year', scopes.time_stamp) = 2008 THEN answ_count end) AS Year7,
count(CASE WHEN date_part('year', scopes.time_stamp) = 2009 THEN answ_count end) AS Year8,
count(CASE WHEN date_part('year', scopes.time_stamp) = 2010 THEN answ_count end) AS Year9,
count(CASE WHEN date_part('year', scopes.time_stamp) = 2011 THEN answ_count end) AS Year10,
count(CASE WHEN date_part('year', scopes.time_stamp) = 2012 THEN answ_count end) AS Year11,
count(CASE WHEN date_part('year', scopes.time_stamp) = 2013 THEN answ_count end) AS Year12,
count(CASE WHEN date_part('year', scopes.time_stamp) = 2014 THEN answ_count end) AS Year13,
count(CASE WHEN date_part('year', scopes.time_stamp) = 2015 THEN answ_count end) AS Year14,
count(CASE WHEN date_part('year', scopes.time_stamp) = 2016 THEN answ_count end) AS Year16
FROM
companies companies,value_scopes value_scopes,dp_values dp,dp_definition def,dp_content_definition cd
where
value_scopes.company_id = companies.company_id
and value_scopes.value_scope_id=dp.value_scope_id
and dp.dp_content_definition_id=cd.dp_content_definition_id
and def.dp_definition_id=cd.dp_definition_id
and value_scopes.is_partial='f'
group by companies.name
ORDER BY companies.name;
DISTINCT ist keine Funktion (auf einer Säule), es ist ein Teil von SELECT DISTINCT' und Werken im ganzen ausgewählte Zeilen. I.e 'SELECT distinct (c1), c2' eq' SELECT DISTINCTc1, c2' eq 'SELECT DISTINCTc1, (c2)'. – jarlh
Wechseln Sie zur modernen expliziten JOIN-Syntax. Einfacher zu schreiben (ohne Fehler), einfacher zu lesen (und zu pflegen) und einfacher in Outer Join zu konvertieren, falls erforderlich. – jarlh
Schätzen Sie den Vorschlag ... Ich weiß nicht, wie man eine Abfrage für solche irgendwie anzeigen. – SUDARSHAN