Ajax-Datentyp JSON funktioniert nicht

Question

Ich versuche, Daten mit AJAX JSON einzufügen, aber es funktioniert nicht. Ich habe es ohne JSON versucht und es funktioniert, aber eine Alarmbox zeigt mit etwas HTML-Code.

HTML:

<a href="#" id="sbreak" onclick="return sbreak();">Short Break</a> 

AJAX:

$(document).ready(function() { 
    $('#sbreak').on('click', function() { 
    var name = $("SBreak").val(); 
    $.ajax({ 
     type: "POST", 
     dataType: 'json', 
     url: "brkrequest.php", 
     data: { 
     sname: name 
     } 
     cache: false, 
     success: function(server_response) { 
     if (server_response.status == '1') //if ajax_check_username.php return value "0" 
     { 
      alert("Inserted "); 
     } else if (server_response == '0') //if it returns "1" 
     { 
      alert("Already Inserted"); 
     } 
     }, 
    }); 
    return false; 
    }); 
}); 

PHP:

session_start(); 
date_default_timezone_set('Asia/Kolkata'); 
$sname=$_POST['sname']; 
$sname= $_SESSION['myusername']; 
$reqdate = date("Y-m-d H:i:s"); 
include("connection.php"); 
//Insert query 
$query = sprintf("SELECT * FROM `breakqueue` WHERE (`sname` ='$sname')"); 

$result = mysql_query($query); 
if(mysql_num_rows($result) > 0){  
    $data['status']= '1';//If there is a record match Already Inserted 
} 
else { // if there is no matching rows do following 
    $query = mysql_query("INSERT INTO `breakqueue`(`id`, `sname`, `btype`, `reqdate`, `apdate`, `status`) VALUES ('','$sname','Sbreak','$reqdate','','Pending')"); 

    $data['status']= '0';//Record Insered 
} 

echo json_encode($data); 
} 

Answer 1

vielleicht Typo

else if(server_response.status == '0')//if it returns "1" 

Answer 2

verwenden Sie es in PHP header('Content-Type:application/json');

und

success: function(server_response){ 
    console.log(typeof server_response); 
... 

für die Suche nach Antworttyp schreiben, wenn Art von server_response ist nicht object

es für convert verwenden, um das Objekt:

server_response = JSON.parse(server_response); 

php Code:

session_start(); 

//Here added... 
header('Content-Type:application/json'); 

date_default_timezone_set('Asia/Kolkata'); 
$sname=$_POST['sname']; 
$sname= $_SESSION['myusername']; 
$reqdate = date("Y-m-d H:i:s"); 
include("connection.php"); 
//Insert query 
$query = sprintf("SELECT * FROM `breakqueue` WHERE (`sname` ='$sname')"); 

    $result = mysql_query($query); 
    if(mysql_num_rows($result) > 0){ 

$data['status']= '1';//If there is a record match Already Inserted 
    } 
    else{ // if there is no matching rows do following 
$query = mysql_query("INSERT INTO `breakqueue`(`id`, `sname`, `btype`, `reqdate`, `apdate`, `status`) VALUES ('','$sname','Sbreak','$reqdate','','Pending')"); 

$data['status']= '0';//Record Insered 
} 

echo json_encode($data); 
} 

Javascript-Code:

$(document).ready(function() 
    { 
    $('#sbreak').on('click', function(){ 
    var name = $("SBreak").val(); 
    $.ajax({ 
    type: "POST", 
    dataType:'json', 
    url: "brkrequest.php", 
    data: {sname: name} 
    cache: false, 
    success: function(server_response){ 
     //TODO:REMOVE IT After seeing. alert or console.log for seeing type 
     alert(typeof server_response); 

     if(typeof server_response){ 
      server_response = JSON.parse(server_response); 
      } 


     if(server_response.status == '1')//if ajax_check_username.php return value "0" 
     { 
      alert("Inserted "); 
     } 
     else if(server_response == '0')//if it returns "1" 
     { 
     alert("Already Inserted"); 
     } 
    }, 
    }); 
    return false;