PHP - get_header wirft Fehler: Dateiname kann nicht leer sein

Question

Dies ist ganze Code, den ich verwendet, die auf einigen anderen Seiten funktioniert, aber auf Google nicht der Fall ist und wirft mir einen Fehler:

$url = 'http://www.google.com'; 
$sitemap = $url.'/sitemap.xml'; 
$robots = $url.'/robots.txt'; 
$robotsx = [$sitemap, $robots]; 
$sitemaps = false; 
$robotss = false; 

//GET REDIRECTED URL 
function getRedirectUrl ($robotsx) { 
    stream_context_set_default(array(
     'http' => array(
     'method' => 'HEAD' 
    ) 
)); 
$headers = get_headers($robotsx, 1); 
if (isset($headers['Location'])) { 
    return is_array($headers['Location']) ? array_pop($headers['Location']) : $headers['Location']; 
} 
return false; 
} 

$finalr = getRedirectUrl($robots); 
$finals = getRedirectUrl($sitemap); 

// IF THERE IS NO REDIRECTED URL 
if ($finalr == null){ 
    $robotss = $robots; 
} 
if ($finals == null){ 
    $sitemaps = $sitemap; 
} 


// GET RESPONSE CODE 
function get_http_response_coder ($url) { 
    $headersyy = get_headers($url); 
    return substr($headersyy[0], 9, 3); 
} 
print_r(get_http_response_coder($url)); 

// CHECK MAIN URL FOR REDIRECT 
$xgetheads = get_headers($url, 1); 

// IF THERE IS REDIRECT 
if (isset($xgetheads['Location'])) { 
    if (isset($finalr)){ 
       $get_http_response_coder = get_http_response_coder($finalr); 
    if ($get_http_response_coder != 404) { 
     echo "Your website have robots file. Your robots file is at ".$finalr; 
    } 
    else{ 
     echo "Your website does not have robots file."; 
    } 
    } 
    if ($finalr == null){ 
       $get_http_response_coder = get_http_response_coder($robotss); 
    if ($get_http_response_coder != 404) { 
     echo "Your website have robots file. Your robots file is at ".$robotss; 
    } 
    else{ 
     echo "Your website does not have robots file."; 
    } 
    }  
    if(isset($finals)){ 
    $get_http_response_codes = get_http_response_coder($finals); 


    if ($get_http_response_codes != 404) { 
     echo "Your website have sitemap file. Your sitemap file is at ".$finals; 
    } 
    else{ 
     echo "Your website does not have sitemap file."; 
    } 
    } 
    if($finals == null){ 
    $get_http_response_codes = get_http_response_coder($sitemaps); 


    if ($get_http_response_codes != 404) { 
     echo "Your website have sitemap file. Your sitemap file is at ".$sitemaps; 
    } 
    else{ 
     echo "Your website does not have sitemap file."; 
    } 
    }  
} 

// IF THERE IS NO REDIRECT 
else{ 
    $get_http_response_coder = get_http_response_coder($robots) ; 
    $get_http_response_codes = get_http_response_coder($sitemap); 

    if ($get_http_response_coder != 404) { 
     echo "Your website have robots file. Your robots file is at ".$robots; 
    } 
    else{ 
     echo "Your website does not have robots file."; 
    } 
    if ($get_http_response_codes != 404) { 
     echo "Your website have sitemap file. Your sitemap file is at ".$sitemap; 
    } 
    else{ 
     echo "Your website does not have sitemap file."; 
    } 
} 

Ich erhalte Fehler:

Warning: get_headers(): Filename cannot be empty 

aber wenn ich nur diesen Teil drucke, bekomme ich den richtigen Antwortcode. Warum passiert das und was ist falsch an meinem Code?

Answer 1

die URL in http: // Format:

function get_http_response_coder ($url) { 
$headersyy = get_headers($url); 
return substr($headersyy[0], 9, 3); 
} 
$url="http://localhost/sample/stackoverflow/fileresp.txt"; 
var_dump(get_http_response_coder($url));