Wählen Sie nur übereinstimmenden Wert in Sql mit Codeigniter

Question

Ich habe 6 weitere Tabellen in MySQL und jedes Feld hat ein eindeutiges Feld 'Works_id', ich gebe Daten diese Tabelle ein. Ich möchte nur übereinstimmenden Wert es zeigt, aber es dauert 16 Zeilen. Angenommen, im Worker-Name-Feld zeigt es zwei Namen mit 8 Wiederholungen, aber ich möchte nur einmal zwei Namen. Es kann zwei Zeilen dauern. Aber wie es möglich ist. My Table Show:

 
Ser Works ID Date Of Works Infrastructure Name of System Type of Works  Vendor Name  Worker Name  
1 1016 2017-03-12  Server   JoinBDApps  Trobleshooting  Vintage IT  Md Rajaon 
2 1016 2017-03-12  Server   JoinBDApps  Software Upgrade Vintage IT  Md Rajaon 
3 1016 2017-03-12  Network   JoinBDApps  Trobleshooting  Vintage IT  Md Rajaon 
4 1016 2017-03-12  Network   JoinBDApps  Software Upgrade Vintage IT  Md Rajaon 
5 1016 2017-03-12  Server   CMH    Trobleshooting  Vintage IT  Md Rajaon 
6 1016 2017-03-12  Server   CMH    Software Upgrade Vintage IT  Md Rajaon 
7 1016 2017-03-12  Network   CMH    Trobleshooting  Vintage IT  Md Rajaon 
8 1016 2017-03-12  Network   CMH    Software Upgrade Vintage IT  Md Rajaon 
9 1016 2017-03-12  Server   JoinBDApps  Trobleshooting  GP IT   Md Forkan 
10 1016 2017-03-12  Server   JoinBDApps  Software Upgrade GP IT   Md Forkan 
11 1016 2017-03-12  Network   JoinBDApps  Trobleshooting  GP IT   Md Forkan 
12 1016 2017-03-12  Network   JoinBDApps  Software Upgrade GP IT   Md Forkan 
13 1016 2017-03-12  Server   CMH    Trobleshooting  GP IT   Md Forkan 
14 1016 2017-03-12  Server   CMH    Software Upgrade GP IT   Md Forkan 
15 1016 2017-03-12  Network   CMH    Trobleshooting  GP IT   Md Forkan 
16 1016 2017-03-12  Network   CMH    Software Upgrade GP IT   Md Forkan 

Aber ich will:

 
Ser Works ID Date Of Works Infrastructure Name of System Type of Works Vendor Name  Worker Name  
1 1016 2017-03-12  Server   JoinBDApps  Trobleshooting Vintage IT  Md Rajaon 
          Network   CMH    Software Upgrade GP IT   Md Forkan 

Mein Codeigniter Modell ist:

 
$this->db->select('trxn_tbl.works_id, trxn_tbl.works_date, infrashtructure_txn_info.infrashtructure_name, apps_txn_tbl.apps_name, works_type_txn_tbl.works_type, workers_tbl.vendor_id, workers_tbl.name'); 
     $this->db->from('infrashtructure_txn_info'); 
     $this->db->join('workers_tbl', 'trxn_tbl.works_id = workers_tbl.works_id'); 
     $this->db->join('works_type_txn_tbl', 'trxn_tbl.works_id = works_type_txn_tbl.works_id'); 
     $this->db->join('infrashtructure_txn_info', 'trxn_tbl.works_id = infrashtructure_txn_info.works_id'); 
     $this->db->join('apps_txn_tbl', 'trxn_tbl.works_id = apps_txn_tbl.works_id'); 
     $query = $this->db->get(); 

     return $query->result(); 

Bitte jemand mir helfen ...

Answer 1

Setzen Sie die distinct() in der Spitze Ihres Codes wie folgt:

$this->db->distinct(); 
$this->db->select('trxn_tbl.works_id, trxn_tbl.works_date, infrashtructure_txn_info.infrashtructure_name, apps_txn_tbl.apps_name, works_type_txn_tbl.works_type, workers_tbl.vendor_id, workers_tbl.name'); 
...rest of your code... 

Hilft das?

Answer 2

sollten Sie GROUP BY verwenden, um die Zeilen zu aggregieren:

$this->db->group_by(array('trxn_tbl.works_id', 'infrashtructure_txn_info.infrashtructure_name')); 

Versuchen Sie, ob das funktioniert:

$this->db->select('trxn_tbl.works_id, trxn_tbl.works_date, infrashtructure_txn_info.infrashtructure_name, apps_txn_tbl.apps_name, works_type_txn_tbl.works_type, workers_tbl.vendor_id, workers_tbl.name'); 
$this->db->from('infrashtructure_txn_info'); 
$this->db->join('workers_tbl', 'trxn_tbl.works_id = workers_tbl.works_id'); 
$this->db->join('works_type_txn_tbl', 'trxn_tbl.works_id = works_type_txn_tbl.works_id'); 
$this->db->join('infrashtructure_txn_info', 'trxn_tbl.works_id = infrashtructure_txn_info.works_id'); 
$this->db->join('apps_txn_tbl', 'trxn_tbl.works_id = apps_txn_tbl.works_id'); 

$this->db->group_by(array('trxn_tbl.works_id', 'infrashtructure_txn_info.infrashtructure_name')); 

$query = $this->db->get(); 

return $query->result(); 

EDIT: Wenn Sie group_by Fehlern erhalten, versuchen von allen zur Gruppe benannte Spalten in Ihrer Auswahl. Eine andere Alternative besteht darin, GROUP_CONCAT für alle Spalten zu verwenden, die nicht in der Klausel group_by enthalten sind. Zum Beispiel: GROUP_CONCAT(workers_tbl.name SEPARATOR ",") as workers_tbl.name usw.