können Sie existiert für diese Abfrage-Methode verwenden. Überprüfen Sie das folgende Beispiel.
using System;
using System.Collections.Generic;
using System.Linq;
namespace ConsoleApplication1
{
public class Car
{
public string CarBrand { get; set; }
public List<CarModel> carModel;
}
public class CarModel
{
public string Name { get; set; }
public string YearOfProduction { get; set; }
}
class Program
{
static void Main(string[] args)
{
var list = new List<Car>();
list.Add(
new Car
{
CarBrand = "Ford",
carModel = new List<CarModel>{
new CarModel{Name="Fiesta", YearOfProduction="2010"},
new CarModel{Name="Fiesta", YearOfProduction="2011"},
new CarModel{Name="Fiesta", YearOfProduction="2012"},
new CarModel{Name="Fiesta", YearOfProduction="2013"},
new CarModel{Name="Fiesta", YearOfProduction="2014"},
new CarModel{Name="Fiesta", YearOfProduction="2015"},
new CarModel{Name="Fiesta", YearOfProduction="2016"},
new CarModel{Name="Mondeo", YearOfProduction="2010"},
new CarModel{Name="Mondeo", YearOfProduction="2011"},
new CarModel{Name="Mondeo", YearOfProduction="2012"},
new CarModel{Name="Mondeo", YearOfProduction="2013"},
new CarModel{Name="Mondeo", YearOfProduction="2014"},
new CarModel{Name="Mondeo", YearOfProduction="2015"},
new CarModel{Name="Mondeo", YearOfProduction="2016"},
new CarModel{Name="Focus", YearOfProduction="2010"},
new CarModel{Name="Focus", YearOfProduction="2011"},
new CarModel{Name="Focus", YearOfProduction="2012"},
new CarModel{Name="Focus", YearOfProduction="2013"},
new CarModel{Name="Focus", YearOfProduction="2014"},
new CarModel{Name="Focus", YearOfProduction="2015"},
}
}
);
list.Add(new Car
{
CarBrand = "Volkswagen",
carModel = new List<CarModel>{
new CarModel{Name="Polo", YearOfProduction="2010"},
new CarModel{Name="Polo", YearOfProduction="2011"},
new CarModel{Name="Polo", YearOfProduction="2012"},
new CarModel{Name="Polo", YearOfProduction="2013"},
new CarModel{Name="Polo", YearOfProduction="2014"},
new CarModel{Name="Polo", YearOfProduction="2015"},
new CarModel{Name="Golf", YearOfProduction="2010"},
new CarModel{Name="Golf", YearOfProduction="2011"},
new CarModel{Name="Golf", YearOfProduction="2012"},
new CarModel{Name="Golf", YearOfProduction="2013"},
new CarModel{Name="Golf", YearOfProduction="2014"},
new CarModel{Name="Golf", YearOfProduction="2015"},
new CarModel{Name="Passat", YearOfProduction="2010"},
new CarModel{Name="Passat", YearOfProduction="2011"},
new CarModel{Name="Passat", YearOfProduction="2012"},
new CarModel{Name="Passat", YearOfProduction="2013"},
new CarModel{Name="Passat", YearOfProduction="2014"},
new CarModel{Name="Passat", YearOfProduction="2015"},
}
});
var newCars = list.Where(s => s.carModel.Exists(m => m.YearOfProduction == "2016"));
foreach (var brand in newCars)
{
foreach (var model in brand.carModel)
{
Console.WriteLine("Brand:{0}, Model:{1}, YearOfPrd:{2}", brand.CarBrand, model.Name, model.YearOfProduction);
}
}
Console.ReadLine();
}
}
}
Welche Linq-Abfragen haben Sie ausprobiert? –
var temp = Autos.SelectMany (x => x.CarModel) .Where (c => c.YearOfProduction == Jahr) .ToList(); aber das gibt mir nur neue Liste –
matihuf
Können Sie diesen Beispielcode zu Ihrer Frage hinzufügen? Es ist wichtig, Ihnen eine Antwort zu geben. –