Wie bekomme ich die Summe von MonthYear in sql?

Question

Ich habe eine Tabelle wie diese

id   Date    Amount 

    1 2016-09-29 09:25:37.000 25.13 
    2 2016-08-01 17:20:39.000 598.00 
    3 2016-09-29 09:24:47.000 15.60 
    4 2016-07-28 17:50:11.000 61.80  
    5 2016-07-28 17:53:56.000 31.40 
    6 2016-07-22 10:40:27.000 74.16 

Ich versuche, zwei Spalten so zu erhalten,

MonthYear   Total 

Sep 2016    40.73 
Aug 2016   598.00 
Jul 2016   167.36 

Aber ich letztes Jahr und Monat nach oben zu bekommen.

Answer 1

diese SQL-Versuchen,

SELECT CONVERT(CHAR(4), Date, 100) + CONVERT(CHAR(4), Date, 120) 
     AS MonthYear, SUM(Amount) 
     AS Total, 
      CAST(CONVERT(varchar(4), Date, 120) AS int) 
     AS Year, DATEPART(m, Date) As Month 
    FROM your_table 
GROUP BY CONVERT(CHAR(4), Date, 100) + CONVERT(CHAR(4), Date,120),CAST(CONVERT(varchar(4), Date, 120) AS int), DATEPART(m, Date) 
ORDER BY Year DESC, Month DESC 

Answer 2

unter

SELECT Datename(MONTH, [Date]) month_name, 
     Year([Date]) year, 
     Sum([Amount]), 
     Month([date]) month_no 
FROM #Table1 
GROUP BY Datename(MONTH, [Date]), 
      Year([Date]), 
      Month([date]) 
ORDER BY Month([date]) DESC, 
      Year([Date]), 
      Datename(MONTH, [Date]) 

Answer 3

Nur eine andere Perspektive Versuchen.

Abfrage

SELECT t.[MonthYear], SUM(t.[Amount]) AS [Total] FROM(
    SELECT RIGHT((CONVERT(VARCHAR(11), [Date], 106)), 8) as [MonthYear], [Amount] 
    FROM [your_table_name] 
)t 
GROUP BY t.[MonthYear];