Ohne regexp Sie die antworten müssen Die gleiche Logik für jede Teilkette, die Sie benötigen, jedes Timi, das die Anfangsposition und die Länge basierend auf der Position von th e "Terminator" dieser Teilkette.
/* input data */
with yourTable(column1) as (
select '/opt/log/data/abcd.efghi.jklmn.aaa.txt' from dual union all
select '/opt/log/data/abbbcd.efccghi.jkdsdflmn.abab.txt' from dual union all
select '/opt/log/data/nmvcnmcd.efjhjghi.jkvslmn.abcbc.txt' from dual union all
select '/opt/log/data/hjsdhj.hjfdhdf.hdfhjd.aghag.txt' from dual union all
select '/opt/log/data/dfhjfdhj.yureyer.qwtyq.hjahjh.txt' from dual
)
/* query */
select substr(column1, instr(column1, '/', -1) +1, instr(column1, '.') - instr(column1, '/', -1)-1) firstDot,
substr(column1, instr(column1, '.') +1, instr(column1, '.', 1, 2) - instr(column1, '.') -1) secondDot,
substr(column1, instr(column1, '.', 1, 2) +1, instr(column1, '.', 1, 4) - instr(column1, '.', 1, 2) -1) thirdAndFourthDot
from yourTable
gibt:
FIRSTDOT SECONDDOT THIRDANDFOURTHD
--------------- --------------- ---------------
abcd efghi jklmn.aaa
abbbcd efccghi jkdsdflmn.abab
nmvcnmcd efjhjghi jkvslmn.abcbc
hjsdhj hjfdhdf hdfhjd.aghag
dfhjfdhj yureyer qwtyq.hjahjh
In einer lesbaren Weise:
select substr(column1, lastSlashPos +1, firstDotPos - lastSlashPos -1) as firstDot,
substr(column1, firstDotPos +1, secondDotPos - firstDotPos -1) as secondDot,
substr(column1, secondDotPos +1, fourthDotPos - secondDotPos -1) as thirdAndFourthDot
from (
select instr(column1, '/', -1) as lastSlashPos,
instr(column1, '.') as firstDotPos,
instr(column1, '.', 1, 2) as secondDotPos,
instr(column1, '.', 1, 3) as thirdDotPos,
instr(column1, '.', 1, 4) as fourthDotPos,
column1
from yourTable
)
danke das funktioniert – user3845185