Partition von, um das korrekte Datum zu erhalten

Question

Ich möchte das älteste Datum unter der FirstScanned Spalte abrufen. Mein Problem ist, dass ein Produkt wieder als neues Produkt zu einem bestimmten Zeitpunkt registriert werden kann, wenn dies geschieht, ich die das älteste gescannten Datum auf dem neuesten Scan Location based sein FirstScanned möchte abrufen 1

im folgenden Beispiel versuche ich die richtige FirstScanned Datum ohne Erfolg abzurufen:

CREATE TABLE [dbo].[Products123](
[ID] [int] NOT NULL, 
[GTIN] [varchar](50) NULL, 
[LocationID] [int] NULL, 
[UserID] [int] NULL, 
[Created] [datetime]) 

insert into Products123(ID, GTIN, LocationID, UserID, Created) 
Values(1, '12345678910', 1, 3, '2017-06-30 14:58:07.693'), -- Location "1" is when products was registered/scanned for this first time 
     (2, '12345678910', 5, 3, '2017-06-30 15:25:12.287'), -- The product is scanned into a new location 
     (3, '12345678910', 17, 3, '2017-06-30 14:58:07.693'), -- The product is now scanned into the "end" location and is considered to be closed 
     (4, '12345678910', 1, 7, '2017-08-01 11:34:16.347'), -- A month later the same productID has been registered, 
     (5, '12345678910', 4, 7, '2017-08-01 11:36:16.460') -- etc 


    DECLARE @Prev8workingdays date = CASE 
     WHEN datepart(dw, getdate()) IN (2,3,4) THEN dateadd(day,-14, getdate()) 
     WHEN datepart(dw, getdate()) IN (1) THEN dateadd(day,-13, getdate()) 
     ELSE dateadd(day,-12, getdate()) 
    END 
    DECLARE @Pre6WorkingDay date = CASE 
     WHEN datepart(dw, getdate()) IN (2) THEN dateadd(day,-9, getdate()) 
     WHEN datepart(dw, getdate()) IN (1) THEN dateadd(day,-8, getdate()) 
     ELSE dateadd(day,-7, getdate()) 
    END 

    select p.GTIN, p.FirstScanned as FirstScan, p.Created As lastScan 
from 
(
    select p.GTIN 
     ,p.LocationID 
     ,p.Created 
     ,min(p.Created) over (partition by p.GTIN) as FirstScanned 
     ,max(p.Created) over (partition by p.GTIN) as LastScanned 
    from Products123 p 
) p 
where p.LastScanned = p.Created and LocationID not in (15,16,17) AND p.FirstScanned < @Prev8workingdays 
Order by FirstScanned 

Mein Ergebnis sieht wie folgt aus:

GTIN  |  FirstScanned  | LastScanned  
    12345678910 | 2017-06-30 14:58:07.693 |2017-08-01 11:36:16.460 

Aber es sollte sein:

GTIN  |  FirstScanned  | LastScanned  
    12345678910 | 2017-08-01 11:34:16.347 |2017-08-01 11:36:16.460 

Answer 1

Sie können nur mit einer einfachen Fallanweisung dorthin gelangen. Nehmen Sie das maximale Datum für Standort 1, und das ist das späteste Datum

select p.GTIN, p.FirstScanned as FirstScan, p.Created As lastScan 
from 
(
    select p.GTIN 
     ,p.LocationID 
     ,p.Created 
     ,max(case when p.LocationID=1 then p.Created else null end) over (partition by p.GTIN) as FirstScanned 
     ,max(p.Created) over (partition by p.GTIN) as LastScanned 
    from Products123 p 
) p 
where p.LastScanned = p.Created and LocationID not in (15,16,17) AND p.FirstScanned < @Prev8workingdays