mysqli_query(): Leere Abfrage

Question

Ich bin Fehler von

mysqli_query(): Empty query in if(mysqli_query($link, $result)){

Catchable fatal error: Object of class mysqli_result could not be converted to string in line echo "ERROR: Could not able to execute $sql. " . mysqli_error($link);

bekommen Darf ich wissen, was das Problem hier ist?

<?php 

$link = mysqli_connect("localhost", "root", "", "databasename") or die("could not connect to mysql"); 
$email = $_SESSION['USEREMAIL']; 
$password = $_SESSION['USERPASS']; 
$sql= mysqli_query($link, "SELECT * FROM admin WHERE email='$email' and password ='$password' "); 
if (isset($_POST["submit"])) { 
    $test = mysqli_real_escape_string($link, $_POST['test']);  
    $result  = mysqli_query($link,"UPDATE admin SET test='$test' WHERE email='$email'"); 

    if(mysqli_query($link, $result)){ 
    echo "Updated successfully."; 
    } else { 
    echo "ERROR: Could not able to execute $sql. " . mysqli_error($link); 
    } 
} 
while ($record = mysqli_fetch_array($sql)) { 
    $test = $record['test']; 
} 
mysqli_close($link); 
?>                

Answer 1

Bitte diesen Code verwenden es Ergebnis korrekt $ wird wird * bereits eine mysqli_query() Sie müssen sich ändern, wenn (mysqli_query ($ link, $ result)) {um so etwas wie if ($ result)) {

session_start(); 
include("header.php"); 
?> 
<?php 

$link = mysqli_connect("localhost", "root", "", "databasename") or die("could not connect to mysql"); 
$email = $_SESSION['USEREMAIL']; 
$password = $_SESSION['USERPASS']; 
$id   = $_SESSION['USERID']; 
$sql= mysqli_query($link, "SELECT * FROM admin WHERE email='$email' and password ='$password' "); 
if (isset($_POST["submit"])) { 
    $test = mysqli_real_escape_string($link, $_POST['test']);  
    $result  = mysqli_query($link,"UPDATE admin SET test='$test' WHERE id='$id'"); 

    if($result){ 
    echo "Updated successfully."; 
    } else { 
    echo "ERROR: Could not able to execute $sql. " . mysqli_error($link); 
    } 
} 
while ($record = mysqli_fetch_array($sql)) { 
    $test = $record['test']; 
} 
mysqli_close($link); 
?> 
<form method="POST" name="testForm" id="testForm" action=""> 
    <div class="form-group"> 
     <div class="input-group"> 
     <input name="test" id="test" placeholder="Test data" class="form-control" type="text" value="<?php echo $test; ?>"> 
     </div> 
    </div> 
<button type="submit" id="submit" class="btn btn-primary btn-md" value="submit" name="submit">Submit</button>