zeigen Daten in der Gruppe von Formiat

Question

Name  Status 
A   Fail 
B   open 
c   fail 
A   Success 
A   open 
A   Success 

Ich möchte Output wie

Name S_open S_Success S_All 
A  1  2   4 
B  1  0   1 
C  0  0   1 

Answer 1

Versuchen Sie, wie dieses

SELECT Name, 
    SUM(CASE WHEN Status='open' THEN 1 END) AS S_open, 
    SUM(CASE WHEN Status='Success' THEN 1 END) AS S_Success, 
    SUM(1) AS S_All 
FROM Table 
GROUP BY Name; 

Answer 2

Sie auch diese versuchen können;

SELECT 
     upper(name), 
     SUM(S_OPEN) S_open, 
     SUM(S_SUCCESS) S_Success, 
     count(*) S_All 
FROM 
(
     select name, 
       CASE WHEN upper(status) = 'OPEN' THEN 1 ELSE 0 END S_OPEN, 
       CASE WHEN upper(status) = 'SUCCESS' THEN 1 ELSE 0 END S_SUCCESS 
     from TABLE 
) t 
GROUP BY upper(name) order by 1