wie Sie Bilder auf einen Webserver hochladen. django

Question

Ich möchte Bilder auf meiner Website anzeigen und ich kann meinen Fehler nicht finden. In anderen Posts habe ich gesehen, dass zu aktualisieren, aber ich habe MEDIA_ROOT und MEDIA_URL wie im Beispiel, aber es hilft mir nicht.

Modelle:

class News(models.Model): 
title = models.CharField(max_length=200, unique=True, 
         verbose_name="Заголовок") 
description = models.TextField(verbose_name="Краткое содержание") 
posted = models.DateField(default=datetime.date.today(), db_index=True, verbose_name="Опубликвана") 
tags = TaggableManager(blank=True, verbose_name="Теги") 
#user = models.ForeignKey(User) 
views = models.IntegerField(default=0) 
likes = models.IntegerField(default=0) 

class Meta: 
    ordering = ['-posted'] 
    verbose_name = "новость" 
    verbose_name_plural = "нвости" 

def get_image_filename(self, filename): 
    title = self.News.title 
    slug = slugify(title) 
    return "post_images/%s-%s" % (slug, filename) 


class Images(models.Model): 
post = models.ForeignKey(News, default=None, related_name="image") 
image = models.ImageField(upload_to=settings.MEDIA_ROOT, 
          verbose_name="Image") 

Einstellungen

MEDIA_ROOT = os.path.join(BASE_DIR, 'media') 
MEDIA_URL = '/media/'` 

Ansicht

def news(request): 
context = RequestContext(request) 
ImageFormSet = modelformset_factory(Images, form=ImageForm, 
            extra=3) 
if request.method == 'POST': 
    form = NewsForm(request.POST) 
    formset = ImageFormSet(request.POST, request.FILES, 
          queryset=Images.objects.none()) 
    if form.is_valid() and formset.is_valid(): 
     post_form = form.save(commit=False) 
     #post_form.user = request.user 
     post_form.save() 
     for forma in formset.cleaned_data: 
      try: 

       image = forma['image'] 
       photo = Images(post=post_form, image=image) 
       photo.save() 
       messages.add_message(request, messages.SUCCESS, 
            "!!!") 
      except KeyError: 
       pass 
     return redirect("main") 
    else: 
     print(form.errors, formset.errors) 
else: 
    form = NewsForm() 
    formset = ImageFormSet(queryset=Images.objects.none()) 
try: 
    page_num = request.GET.get('page') 
except KeyError: 
    page_num = 1 
images = Images.objects 
all_news = News.objects.all() 
paginator = Paginator(all_news, 10) 
try: 
    pages = paginator.page(page_num) 
except InvalidPage: 
    pages = paginator.page(1) 
return render_to_response("mainpage.html", {'form': form, 'formset': formset, 
              'pages': pages, 'news': images}, context) 

und Vorlage

{% block content %} 
    {% for new in pages %} 
    <h2>{{ new.title }}</h2> 

    <img src="{{ new.image.url}}"> 

{% endfor %} 


<form action="" method="post" enctype="multipart/form-data"> 
{% include "generic/form.html" %} 
<input type="submit" value="создать"> 
</form> 
{% endblock %} 

Wo ist mein Fehler?

Answer 1

{% for new in news %} 
<h2>{{ new.title }}</h2> 
    {% for image in new.image.all %} 
    <img src="{{image.image.url }}"> 
    {% endfor %} 

Da post = models.ForeignKey (News, default = None, related_name = "image") viele Bilder hat.

Answer 2

Diese Zeile:

Bilder = Images.objects

Ändern es auf Bilder = Images.objects.all() und prüfen, ob es funktioniert?