Sicher funktioniert das gut. (Verwenden Sie https fiddle für Chrome):
function Hop() {
this.pc1 = new RTCPeerConnection();
this.pc2 = new RTCPeerConnection();
var add = (pc, can) => can && pc.addIceCandidate(can).catch(log);
this.pc1.onicecandidate = e => add(this.pc2, e.candidate);
this.pc2.onicecandidate = e => add(this.pc1, e.candidate);
this.pc2.oniceconnectionstatechange = e => log(this.pc2.iceConnectionState);
};
Hop.prototype.send = function(stream) {
this.pc1.addStream(stream);
return Promise.all([
new Promise(resolve => this.pc2.onaddstream = resolve),
this.pc1.createOffer()
.then(offer => this.pc1.setLocalDescription(offer))
.then(() => this.pc2.setRemoteDescription(this.pc1.localDescription))
.then(() => this.pc2.createAnswer())
.then(answer => this.pc2.setLocalDescription(answer))
.then(() => this.pc1.setRemoteDescription(this.pc2.localDescription))
])
.then(results => results[0].stream);
};
var AtoB = new Hop(), BtoC = new Hop();
navigator.mediaDevices.getUserMedia({ video: true })
.then(stream => AtoB.send(v1.srcObject = stream))
.then(stream => BtoC.send(v2.srcObject = stream))
.then(stream => v3.srcObject = stream)
.catch(e => log(e));
var log = msg => div.innerHTML += msg + "<br>";
<video id="v1" height="120" width="160" autoplay muted></video>
<video id="v2" height="120" width="160" autoplay></video>
<video id="v3" height="120" width="160" autoplay></video><br>
<div id="div"></div>
<script src="https://webrtc.github.io/adapter/adapter-latest.js"></script>
Sie so viele Hopfen erstellen können, wie Sie möchten.
Fock, haben wir eine Probe für das auch :-) https://webrtc.github.io/samples/src/content/peerconnection/multiple-relay/ –
Warum nicht verschlechtert die Qualität? Wird es neu codiert oder werden Pakete gelöscht? – transistor09
wir dürfen entfernte Streams übertragen ?, verdammt, das wusste ich nie – mido