MySQL Subquery Looping für jede zurückgegebene Zeile

Question

Dies verwendet zwei Abfragen und ich möchte das Ergebnis für jede Zeilen in der ersten Unterabfrage, die die zweite Abfrage zurückgegeben wird, erhalten, im Wesentlichen wird dies wie eine foreach-Schleife handeln. Ich hoffe, es gibt jemanden, der das schnell herausfinden kann.

CREATE TABLE `File_Structure`(
    `id` INT PRIMARY KEY AUTO_INCREMENT, 
    `name` VARCHAR(255) NOT NULL DEFAULT '', 
    `is_folder` TINYINT(1) NOT NULL DEFAULT 0, 
    `lft` INT NOT NULL DEFAULT 0, 
    `rht` INT NOT NULL DEFAULT 0, 
    `is_active` TINYINT(1) NOT NULL DEFAULT 1, 
    `created` TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP, 
    `modified` DATETIME NOT NULL DEFAULT '0000-00-00 00:00:00' 
)ENGINE=InnoDB; 
INSERT INTO `file_structure` (`id`, `name`, `is_folder`, `lft`, `rht`, `is_active`, `created`, `modified`) VALUES 
    (1, 'Code', 1, 1, 12, 1, '2017-11-26 00:13:40', '0000-00-00 00:00:00'), 
    (2, 'Account', 1, 2, 7, 1, '2017-11-26 00:13:40', '0000-00-00 00:00:00'), 
    (3, 'AccountCreate.php', 0, 3, 4, 1, '2017-11-26 00:13:40', '0000-00-00 00:00:00'), 
    (4, 'AccountsFindAll.php', 0, 5, 6, 1, '2017-11-26 00:13:40', '0000-00-00 00:00:00'), 
    (5, 'JournalEntry', 1, 8, 11, 1, '2017-11-26 00:13:41', '0000-00-00 00:00:00'), 
    (6, 'JournalCreate.php', 0, 9, 10, 1, '2017-11-26 00:13:41', '0000-00-00 00:00:00'); 

-- 1. FIND ALL LEAF NODES OF A DESIRED NODE. 
SELECT `name` 
FROM `File_Structure` AS `MAIN`, 
(
    SELECT `lft`, `rht` 
    FROM 
    `File_Structure` 
    WHERE `name`='Account' 
) AS `SUB` 
WHERE `MAIN`.`lft`>`SUB`.`lft` 
AND `MAIN`.`rht`<`SUB`.`rht` 
AND `MAIN`.`rht`=`MAIN`.`lft`+1 
; 
-- 2. FOR A LEAF NODE, GET A PATH UPTO THE DESIRED NODE. 
//SET group_concat_max_len = 2048 TO AVOID THE LIMIT OF 1K STRING LENGTH. 

SELECT GROUP_CONCAT(`SUB`.`name` SEPARATOR '/') AS `CONCATEDNAME` 
FROM 
(
    SELECT `PARENT`.`name` 
    FROM `File_Structure` AS `NODE`, 
    `File_Structure` AS `PARENT` 
    WHERE `NODE`.`lft` BETWEEN `PARENT`.`lft` AND `PARENT`.`rht` 
    AND `NODE`.`name` = 'AccountsFindAll.php' 
    ORDER BY `PARENT`.`lft` 
) AS `SUB` 
; 

-- 3. REPEAT 2 FOR 1 

Answer 1

Es ist viel einfacher zu bedienen als JOIN verschiedenen Ebenen von Unterabfragen:

SELECT GROUP_CONCAT(path.name ORDER BY path.lft SEPARATOR '/') AS CONCATEDNAME 
FROM File_Structure AS root 
JOIN File_Structure AS leaf ON leaf.lft BETWEEN root.lft AND root.rht 
JOIN File_Structure AS path ON leaf.lft BETWEEN path.lft AND path.rht 
WHERE leaf.rht = leaf.lft+1 
AND root.name='Account' 
GROUP BY leaf.name; 

Ausgang:

+----------------------------------+ 
| CONCATEDNAME      | 
+----------------------------------+ 
| Code/Account/AccountCreate.php | 
| Code/Account/AccountsFindAll.php | 
+----------------------------------+