Wie

Question

in Python aus einer Textdatei Artikel von Spalte zu sortieren habe ich die folgenden Elemente in einer Textdatei mit Namen von Städten und dort Quartal Umsatz:

Atlanta 40 50 23 18 
Denver 56 78 34 11 
Miami  40 34 18 30 
Orlando 55 67 23 11 
Memphis 44 23 56 11 
Boston 55 67 33 23 
Tampa  45 67 54 77 

ich das Viertel Probleme habe Umsatz mit Sortierung in Die Liste. Mein aktuelles Programm sieht so aus.

with open('revenue.txt', 'r') as f: 
text = [line.split() for line in f] 
print("{:<12}{:<14}{:>10}{:>9}".format("City", "Revenue", "Total", 
"Average")) 
for a in text: 
    city = a[0] 
    revenue = [int(i) for i in a[1:5]] 
    total = sum(revenue) 
    avg = sum(revenue)/len(revenue) 
    print("{:<12}{}{:>6}{:>9.2f}".format(city, revenue, total, avg)) 

print("\n""Sort the cities by their Quarter 1 revenues.") 

print("\n""Sort the cities by their Quarter 3 revenues.") 

print("\n""Sort the cities by their total revenues.") 

Ich versuche, herauszufinden, wie ich 1. Quartal 3. Quartal und Gesamt Spalten und dann drucken Sie die Stadt sortieren, die mit ihnen verbunden ist. Zum Beispiel:

Sort the cities by their Quarter 1 revenues 
['Miami','Atlanta','Memphis','Tampa','Boston','Orlando','Denver'] 
# [40,40,44,45,55,55,56] 

Jede Hilfe wird geschätzt.

Answer 1

Ich würde ein Wörterbuch zusammen mit einer Liste verwenden, um die Lesbarkeit in Ihrer Sortierung zu erhöhen und wie nützlich Ihr Code ist. Ich ging voran und implementierte eine Funktion zum Drucken der Tabelle (weil Sie es mehrmals in Ihrer Funktion tun). Ich habe auch eine Liste von Wörterbüchern als neuen Datensatz hinzugefügt. Dann habe ich die Funktion sorted verwendet, um Ihre neu organisierte Liste zu erstellen.

with open('revenue.txt', 'r') as f: 
    def print_table(data): 
     for value in data: 
      print("{city:<12}{revenue}{total:>6}{avg:>9.2f}".format(**value)) 
    text = [line.split() for line in f] 
    data = [] 
    for a in text: 
     revenue = [int(i) for i in a[1:5]] 
     data.append({ 
      'city': a[0], 
      'revenue': revenue, 
      'total' : sum(revenue), 
      'avg' : sum(revenue)/len(revenue) 
     }) 
    print("\n""Original data set.") 
    print_table(data) 

    print("\n""Sort the cities by their Quarter 1 revenues.") 
    print_table(sorted(data,key=lambda a: a['revenue'][0])) 

    print("\n""Sort the cities by their Quarter 3 revenues.") 
    print_table(sorted(data,key=lambda a: a['revenue'][2])) 

    print("\n""Sort the cities by their total revenues.") 
    print_table(sorted(data,key=lambda a: a['total'])) 

Answer 2

Sie können es wie folgt sortiert:

text = [ 
["Atlanta", 40,50,23,18 ], 
["Denver ", 56,78,34,11 ], 
["Miami ", 40,34,18,30 ], 
["Orlando", 55,67,23,11 ], 
["Memphis", 44,23,56,11 ], 
["Boston ", 55,67,33,23 ], 
["Tampa ", 45,67,54,77 ]] 


for a in text: 
    city = a[0] 
    revenue = [int(i) for i in a[1:5]] 
    total = sum(revenue) 
    avg = sum(revenue)/len(revenue) 
    # print("{:<12}{}{:>6}{:>9.2f}{:>9.2f}{:>9.2f}".format(city, revenue, total, avg)) 
    a.append(total) # append it to your former array 
    a.append(avg) # append it to your former array 


print ("1.Q") 
printIt(sorted(text, key=lambda x: x[1])) # sort by 1. Quarter number 
print ("2.Q") 
printIt(sorted(text, key=lambda x: x[2])) # sort by 2. Quarter number 
print ("3.Q") 
printIt(sorted(text, key=lambda x: x[3])) # etc. 
print ("4.Q") 
printIt(sorted(text, key=lambda x: x[4])) 
print ("Total") 
printIt(sorted(text, key=lambda x: x[5])) 
print ("Avg") 
printIt(sorted(text, key=lambda x: x[6])) 

sorted(..) wird eine neue Liste Objekt erstellen - Sie einfach es in etwas speichern könnten Sie verwenden möchten - für demonstational Zwecke sie den einfachen Weg gerade gedruckt.

Ausgang:

1.Q 
[ ['Atlanta', 40, 50, 23, 18, 131, 32.75], 
    ['Miami ', 40, 34, 18, 30, 122, 30.5], 
    ['Memphis', 44, 23, 56, 11, 134, 33.5], 
    ['Tampa ', 45, 67, 54, 77, 243, 60.75], 
    ['Orlando', 55, 67, 23, 11, 156, 39.0], 
    ['Boston ', 55, 67, 33, 23, 178, 44.5], 
    ['Denver ', 56, 78, 34, 11, 179, 44.75]] 

2.Q 
[ ['Memphis', 44, 23, 56, 11, 134, 33.5], 
    ['Miami ', 40, 34, 18, 30, 122, 30.5], 
    ['Atlanta', 40, 50, 23, 18, 131, 32.75], 
    ['Orlando', 55, 67, 23, 11, 156, 39.0], 
    ['Boston ', 55, 67, 33, 23, 178, 44.5], 
    ['Tampa ', 45, 67, 54, 77, 243, 60.75], 
    ['Denver ', 56, 78, 34, 11, 179, 44.75]] 

3.Q 
[ ['Miami ', 40, 34, 18, 30, 122, 30.5], 
    ['Atlanta', 40, 50, 23, 18, 131, 32.75], 
    ['Orlando', 55, 67, 23, 11, 156, 39.0], 
    ['Boston ', 55, 67, 33, 23, 178, 44.5], 
    ['Denver ', 56, 78, 34, 11, 179, 44.75], 
    ['Tampa ', 45, 67, 54, 77, 243, 60.75], 
    ['Memphis', 44, 23, 56, 11, 134, 33.5]] 

4.Q 
[ ['Denver ', 56, 78, 34, 11, 179, 44.75], 
    ['Orlando', 55, 67, 23, 11, 156, 39.0], 
    ['Memphis', 44, 23, 56, 11, 134, 33.5], 
    ['Atlanta', 40, 50, 23, 18, 131, 32.75], 
    ['Boston ', 55, 67, 33, 23, 178, 44.5], 
    ['Miami ', 40, 34, 18, 30, 122, 30.5], 
    ['Tampa ', 45, 67, 54, 77, 243, 60.75]] 

Total 
[ ['Miami ', 40, 34, 18, 30, 122, 30.5], 
    ['Atlanta', 40, 50, 23, 18, 131, 32.75], 
['Memphis', 44, 23, 56, 11, 134, 33.5], 
    ['Orlando', 55, 67, 23, 11, 156, 39.0], 
    ['Boston ', 55, 67, 33, 23, 178, 44.5], 
    ['Denver ', 56, 78, 34, 11, 179, 44.75], 
    ['Tampa ', 45, 67, 54, 77, 243, 60.75]] 

Avg 
[ ['Miami ', 40, 34, 18, 30, 122, 30.5], 
    ['Atlanta', 40, 50, 23, 18, 131, 32.75], 
    ['Memphis', 44, 23, 56, 11, 134, 33.5], 
    ['Orlando', 55, 67, 23, 11, 156, 39.0], 
    ['Boston ', 55, 67, 33, 23, 178, 44.5], 
    ['Denver ', 56, 78, 34, 11, 179, 44.75], 
    ['Tampa ', 45, 67, 54, 77, 243, 60.75]] 

Dies gilt, was in How to sort a list of objects based on an attribute of the objects? für Ihr Problem dargestellt. Gekennzeichnete Frage als Duplikat

Answer 3

Sie können pandas verwenden. Es ist so einfach:

import pandas 

with open('revenue.txt', 'r') as f: 
    text = [line.split() for line in f] 

df = pandas.DataFrame(text, columns = ["City", "Revenue", "Total", "Average", "Other"]) 
df_sorted_by_Total = df.sort_values("Total", ascending=True) # Sort by values of the City column 

print(df_sorted_by_Total) 
print(df_sorted_by_Total["City"].tolist()) # Print City column as list 

Ausgang:

 City Revenue Total Average Other 
4 Memphis  44 23  56 11 
2 Miami  40 34  18 30 
0 Atlanta  40 50  23 18 
3 Orlando  55 67  23 11 
5 Boston  55 67  33 23 
6 Tampa  45 67  54 77 
1 Denver  56 78  34 11 
['Memphis', 'Miami', 'Atlanta', 'Orlando', 'Boston', 'Tampa', 'Denver']