Anzeige 4 Bild 1 1

Question

Also habe ich eine Schaltfläche und 4 Pictureboxes und wenn ich auf den Button Ich möchte auf der ersten Bildbox 1 Bild hinzufügen, und wenn ich die Taste das zweite Mal klicken möchte ich die picturebox2 = picturebox1 machen und die PictureBox1 = das neue Bild und so weiter, bis 4 das ist, was ich bisher tat, aber es funktioniert nicht, es zeigt mir, auf den alle 4 PictureBox das gleiche Bild:

namespace ImageUploadAndCameraUse 
{ 
    public partial class Form1 : Form 
    { 
     Image File; 
     Image File2; 
     Image File3; 
     Image File4; 

     bool button1Click = true; 
     bool button1Click2 = true; 
     bool button1Click3 = true; 
     bool button1Click4 = true; 

     public Form1() 
     { 
      InitializeComponent(); 
     } 

     private void button1_Click(object sender, EventArgs e) 
     { 
      OpenFileDialog f = new OpenFileDialog(); 
      f.Filter = "Image files (*.jpg, *.jpeg, *.jpe, *.jfif, *.png) | *.jpg; *.jpeg; *.jpe; *.jfif; *.png"; 

      bool IsNullOrEmpty1 = false; 
      bool IsNullOrEmpty2 = false; 
      bool IsNullOrEmpty3 = false; 

      if (f.ShowDialog() == DialogResult.OK) 
      { 
       if (button1Click) 
       { 
        File = Image.FromFile(f.FileName); 
        pictureBox1.Image = File; 

        IsNullOrEmpty1 = true; 
        button1Click = false; 
       } 
       if (IsNullOrEmpty1 && button1Click2) 
       { 
        File2 = Image.FromFile(f.FileName); 
        pictureBox2.Image = pictureBox1.Image; 
        pictureBox1.Image = File2; 

        IsNullOrEmpty2 = true; 
        button1Click2 = false; 
       } 
       if (IsNullOrEmpty2 && button1Click3) 
       { 
        File3 = Image.FromFile(f.FileName); 
        pictureBox3.Image = File3; 
        IsNullOrEmpty3 = true; 
        button1Click3 = false; 
       } 
       if (IsNullOrEmpty3 && button1Click4) 
       { 
        File4 = Image.FromFile(f.FileName); 
        pictureBox4.Image = File4; 
        button1Click4 = false; 
       } 
      } 
     } 
    } 
} 

und auch wenn Sie wissen: Wie kann ich dieses Programm verwenden, um die Gerätekamera zu verwenden, um ein Foto zu machen, wenn Sie nichts in irgendeiner Bildbox/dem Ordner haben, den ich erstellen werde, um alle diese Fotos zu speichern.

Answer 1

Try-Klon oder instanziiert neues Bitmap für PictureBox:

File2 = Image.FromFile(f.FileName); 
pictureBox2.Image = new Bitmap(pictureBox1.Image); // or pictureBox1.Image.Clone() 
pictureBox1.Image = File2; 

Sie kopieren Referenz, so dass Sie immer das gleiche Bild zeigen.

** EDIT

Versuchen Sie algorith ändern, weil es ein bisschen kompliziert ist:

private List<Image> _images = new List<Image>(); 
private PictureBox[] _pictureBoxes = new [] { pictureBox1, pictureBox2, pictureBox3, pictureBox4 }; 

private void button1_Click(object sender, EventArgs e) { 
    var fileName = GetFileName(); 

    if (string.IsNullOrEmpty(fileName)) return; 

    var image = Bitmap.FromFile(fileName); 
    _images.Insert(0, image); // I don't control items in list, you can remove items when reach count grater than 4 

    for(var i = 0; i < Math.Min(_images.Count, 4); i++) { 
     // _pictureBoxes[i].Image = null; // I'm not sure if this is necessary 
     _pictureBoxes[i].Image = _images[i]; // set image as we store it in list 
    } 
} 

private string GetFileName() { 
    var form = new OpenFileDialog(); 
    form.Filter = "Image files (*.jpg, *.jpeg, *.jpe, *.jfif, *.png) | *.jpg; *.jpeg; *.jpe; *.jfif; *.png"; 

    return form.ShowDialog() == DialogResult.OK ? form.FileName : ""; 
} 

Answer 2

Sie können dies nur eine Schleife durch Ihre PictureBox zu erreichen:

int boxIndex = 0; 

private void button1_Click(object sender, EventArgs e) { 
    OpenFileDialog f = new OpenFileDialog(); 
    f.Filter = "Image files (*.jpg, *.jpeg, *.jpe, *.jfif, *.png) | *.jpg; *.jpeg; *.jpe; *.jfif; *.png"; 
    if (f.ShowDialog() == DialogResult.OK) { 
    PictureBox[] boxes = new PictureBox[] { pictureBox1, pictureBox2, pictureBox3, pictureBox4 }; 
    if (boxIndex + 1 > boxes.Length) { 
     foreach (PictureBox pb in boxes) { 
     pb.Image = null; 
     } 
     boxIndex = 0; 
    } 
    for (int i = boxIndex; i > 0; --i) { 
     boxes[i].Image = boxes[i - 1].Image; 
    } 
    boxes[0].Image = Image.FromFile(f.FileName); 
    boxIndex++; 
    } 
} 

Answer 3

Nevermind gelöst I es selbst mit einem Schalter so:

private void button1_Click(object sender, EventArgs e) 
     { 
      ++NumberOfClick; 
      switch (NumberOfClick) 
      { 
       case 1: 
        OpenFileDialog f = new OpenFileDialog(); 
        f.Filter = "Image files (*.jpg, *.jpeg, *.jpe, *.jfif, *.png) | *.jpg; *.jpeg; *.jpe; *.jfif; *.png"; 

        if (f.ShowDialog() == DialogResult.OK) 
        { 
         File = Image.FromFile(f.FileName); 
         pictureBox1.Image = File; 
        } 

        break; 
       case 2: 
        OpenFileDialog f2 = new OpenFileDialog(); 
        f2.Filter = "Image files (*.jpg, *.jpeg, *.jpe, *.jfif, *.png) | *.jpg; *.jpeg; *.jpe; *.jfif; *.png"; 

        if (f2.ShowDialog() == DialogResult.OK) 
        { 
         File = Image.FromFile(f2.FileName); 
         pictureBox2.Image = pictureBox1.Image; 
         pictureBox1.Image = File; 
        } 
        break; 
       case 3: 
        OpenFileDialog f3 = new OpenFileDialog(); 
        f3.Filter = "Image files (*.jpg, *.jpeg, *.jpe, *.jfif, *.png) | *.jpg; *.jpeg; *.jpe; *.jfif; *.png"; 

        if (f3.ShowDialog() == DialogResult.OK) 
        { 
         File = Image.FromFile(f3.FileName); 
         pictureBox3.Image = pictureBox2.Image; 
         pictureBox2.Image = pictureBox1.Image; 
         pictureBox1.Image = File; 
        } 
        break; 
       case 4: 
        OpenFileDialog f4 = new OpenFileDialog(); 
        f4.Filter = "Image files (*.jpg, *.jpeg, *.jpe, *.jfif, *.png) | *.jpg; *.jpeg; *.jpe; *.jfif; *.png"; 

        if (f4.ShowDialog() == DialogResult.OK) 
        { 
         File = Image.FromFile(f4.FileName); 
         pictureBox4.Image = pictureBox3.Image; 
         pictureBox3.Image = pictureBox2.Image; 
         pictureBox2.Image = pictureBox1.Image; 
         pictureBox1.Image = File; 
        } 

        break; 
       default: 
        // other clicks 
        // . . . 
        break; 

      } 
     }