Zeit Banding mit Mysql Zeit-Datentyp

Question

möchte ich meine Verkäufe Tabelle abzufragen und die Anzahl der deutlichen Empfang Zahlen von Stunde für jeden Tag der Woche

jeder Datensatz erhalten hat eine Quittungsnummer, die Wiederholung der Fall ist, eine datein in Feld, das nur Datum Datentyp und ein sepearte Zeitfeld

hier in dem Zeitdatentyp ist die Abfrage i

select dayname(datein),dayofweek(datein), 
if(hour(timein) between 9 and 11, count(distinct salenbr),0) as `9-11`, 
if(hour(timein) between 11 and 13, count(distinct salenbr),0) as `11-13`, 
if(hour(timein) between 13 and 15, count(distinct salenbr),0) as `13-15`, 
if(hour(timein) between 15 and 17, count(distinct salenbr),0) as `15-17`, 
if(hour(timein) between 17 and 19, count(distinct salenbr),0) as `17-19`, 
if(hour(timein) between 19 and 21, count(distinct salenbr),0) as `19-21` 
from carmanslive.allsales 
where loccode = 'SF' and exitcode in ('64','65') 
and deptname = 'Photofinishing' 
and datein >= DATE_SUB(NOW(), INTERVAL 3 MONTH) 
group by dayname(datein),dayofweek(datein) 
order by dayofweek(datein) 

der Ausgang falsch zu verwenden ist versucht obwohl

<table caption="UnknownTable (7 rows)"> 
    <thead> 
    <tr> 
     <th class="col0">dayname(datein)</th> 
     <th class="col1">dayofweek(datein)</th> 
     <th class="col2">9-11</th> 
     <th class="col3">11-13</th> 
     <th class="col4">13-15</th> 
     <th class="col5">15-17</th> 
     <th class="col6">17-19</th> 
     <th class="col7">19-21</th> 
    </tr> 
    </thead> 
    <tbody> 
    <tr> 
     <td class="col0">Sunday</td> 
     <td class="col1">1</td> 
     <td class="col2">0</td> 
     <td class="col3">118</td> 
     <td class="col4">0</td> 
     <td class="col5">0</td> 
     <td class="col6">0</td> 
     <td class="col7">0</td> 
    </tr> 
    <tr> 
     <td class="col0">Monday</td> 
     <td class="col1">2</td> 
     <td class="col2">0</td> 
     <td class="col3">0</td> 
     <td class="col4">360</td> 
     <td class="col5">360</td> 
     <td class="col6">0</td> 
     <td class="col7">0</td> 
    </tr> 
    <tr> 
     <td class="col0">Tuesday</td> 
     <td class="col1">3</td> 
     <td class="col2">0</td> 
     <td class="col3">390</td> 
     <td class="col4">0</td> 
     <td class="col5">0</td> 
     <td class="col6">0</td> 
     <td class="col7">0</td> 
    </tr> 
    <tr> 
     <td class="col0">Wednesday</td> 
     <td class="col1">4</td> 
     <td class="col2">480</td> 
     <td class="col3">0</td> 
     <td class="col4">0</td> 
     <td class="col5">0</td> 
     <td class="col6">0</td> 
     <td class="col7">0</td> 
    </tr> 
    <tr> 
     <td class="col0">Thursday</td> 
     <td class="col1">5</td> 
     <td class="col2">0</td> 
     <td class="col3">0</td> 
     <td class="col4">0</td> 
     <td class="col5">330</td> 
     <td class="col6">0</td> 
     <td class="col7">0</td> 
    </tr> 
    <tr> 
     <td class="col0">Friday</td> 
     <td class="col1">6</td> 
     <td class="col2">0</td> 
     <td class="col3">380</td> 
     <td class="col4">380</td> 
     <td class="col5">0</td> 
     <td class="col6">0</td> 
     <td class="col7">0</td> 
    </tr> 
    <tr> 
     <td class="col0">Saturday</td> 
     <td class="col1">7</td> 
     <td class="col2">0</td> 
     <td class="col3">0</td> 
     <td class="col4">368</td> 
     <td class="col5">0</td> 
     <td class="col6">0</td> 
     <td class="col7">0</td> 
    </tr> 
    </tbody> 
</table> 

es sollte Daten in jeder Spalte sein, ich habe die Daten bestätigt, ist da.

Answer 1

Ich nehme an, Sie müssen das Aggregat um Ihr if legen. Etwas wie:

select dayname(datein),dayofweek(datein), 
count(distinct if(hour(timein) between 9 and 11, salenbr,0)) as `9-11` 
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