SQL Server 2000 - ein Fremdschlüssel Beziehungen der Tabellenabfrage

Question

fast identisch mit Query a Table's Foreign Key relationships, aber für SQL Server 2000

Für eine gegebene Tabelle ‚foo‘, ich brauche eine Abfrage eine Reihe von Tabellen zu erzeugen, die ausländische haben Schlüssel, die auf foo zeigen.

Answer 1

SELECT o2.name 
FROM sysobjects o 
INNER JOIN sysforeignkeys fk on o.id = fk.rkeyid 
INNER JOIN sysobjects o2 on fk.fkeyid = o2.id 
WHERE o.name = 'foo' 

Answer 2

starten hier

SELECT cons.TABLE_NAME 
    , cons.CONSTRAINT_NAME PK_NAME 
    , cols.COLUMN_NAME 
FROM INFORMATION_SCHEMA.TABLE_CONSTRAINTS cons 
LEFT join INFORMATION_SCHEMA.CONSTRAINT_COLUMN_USAGE cols 
ON cons.CONSTRAINT_NAME = cols.CONSTRAINT_NAME 
WHERE cons.CONSTRAINT_TYPE = 'foreign KEY' 
ORDER BY cons.TABLE_NAME 
    , cons.CONSTRAINT_NAME 
    , cols.COLUMN_NAME 

[Bearbeiten] Formatierung ist alles vermasselt

[edit2] nicht mehr

Answer 3

Versuchen Sie dieses T-SQL:

select col_name(fkeyid, fkey) as column_name, object_name(rkeyid) as referenced_table_name, col_name(rkeyid, rkey) as referenced_column_name from sysforeignkeys where object_name(fkeyid) = 'tableNameHere' order by constid 

Ich habe Die Abfrage wurde leicht umgeschrieben, um Ihnen alle anderen Tabellen zu geben, die sich auf eine bestimmte Tabelle beziehen:

select object_name(fkeyid), 
col_name(fkeyid, fkey) as column_name, 
col_name(rkeyid, rkey) as referenced_column_name 
from sysforeignkeys 
where object_name(rkeyid) = 'tableNameHere' 
order by constid 

Answer 4

Eltern und Kinder

/* this will find out all of the foreign key references for a table*/ 

DECLARE @tableName varchar(128) 
SET @tableName = 'tCounter' 

SELECT 
    pt.[name] AS 'parentTable', 
    ct.[name] AS 'childTable', 
    fk.[name] AS 'fkName', 
* 
FROM sys.foreign_keys fk   
    INNER JOIN sys.tables pt    
     ON pt.object_ID = fk.parent_object_id   
    INNER JOIN sys.tables ct    
     ON ct.object_ID = fk.referenced_object_id 
WHERE pt.name = @tableName  
    OR ct.name = @tableName 
ORDER BY pt.name, ct.name