Stunden zwischen Schichten berechnen

Question

Es gibt ein neues Gesetz, das in einer der Städte, in denen wir tätig sind, in Kraft tritt. Wir müssen mindestens 11 Stunden ab dem Zeitpunkt haben, an dem jemand ausschaltet, bis er einsteigen kann. Wenn die Zeit weniger als 11 Stunden beträgt, müssen wir ihnen für jeden Vorfall einen bestimmten Betrag zahlen.

Ich bin mit SQL Server 2012

Ich brauche Hilfe bei der Bestimmung, welche, wie viele Stunden pro Person zwischen den Schichten hat. Basierend auf den unten stehenden Aufzeichnungen, würden wir für 11/14 11:28 Uhr -> 11/15 8:56 Uhr (9.28 Uhr) und 11/29 2:32 Uhr -> 11/29 10:11 Uhr (7,39 Stunden)

schulden

CREATE TABLE #Shift(
    FKEmployeeNumber int, 
    DateOfBusiness datetime, 
    FKStoreId int, 
    EmployeeShiftNumber int, 
    FKJobCodeId int, 
    InHour int, 
    InMinute int, 
    OutHour int, 
    OutMinute int) 

insert into #Shift (FKEmployeeNumber, DateOfBusiness, FKStoreId, EmployeeShiftNumber, FKJobCodeId, InHour, InMinute,OutHour,OutMinute) 
values 
(529251, '11/13/2017', 3013, 0, 1, 8, 1, 16, 24), 
(529251, '11/14/2017', 3013, 0, 1, 15, 21, 23, 28), 
(529251, '11/15/2017', 3013, 0, 1, 8, 56, 15, 58), 
(529251, '11/16/2017', 3013, 0, 1, 14, 59, 20, 54), 
(529251, '11/19/2017', 3013, 0, 1, 12, 40, 19, 42), 
(529251, '11/20/2017', 3013, 1, 1, 8, 28, 23, 47), 
(529251, '11/21/2017', 3013, 0, 1, 15, 31, 23, 30), 
(529251, '11/25/2017', 3013, 0, 1, 10, 26, 18, 13), 
(529251, '11/27/2017', 3013, 0, 1, 9, 58, 18, 27), 
(529251, '11/28/2017', 3013, 0, 1, 14, 59, 2, 32), 
(529251, '11/29/2017', 3013, 0, 1, 10, 11, 17, 13), 
(529251, '11/29/2017', 3013, 1, 1, 17, 16, 17, 25), 
(529251, '11/30/2017', 3013, 0, 1, 15,4, 20, 0), 
(529251, '11/30/2017', 3013, 1, 1, 20, 0, 23, 18), 
(529251, '11/30/2017', 3013, 2, 1, 23, 18, 23, 22), 
(529251, '12/01/2017', 3013, 0, 1, 12, 12, 16, 0) 


Select 
sh.dateofbusiness,sh.fkstoreid,sh.employeeshiftnumber,sh.fkemployeenumber, sh.fkjobcodeid,sh.inHour,sh.InMinute,sh.OutHour,sh.OutMinute 
from #shift sh where sh.dateofbusiness > '11/12/2017' and sh.fkemployeenumber = 529251 
order by sh.FKEmployeeNumber, sh.DateOfBusiness 

Answer 1

Hier ist ein Weg nach dem Erstellen einiger Datum Zeiten ... mit einem Cte und Self Join.

if object_id('tempdb..#Shift') is not null 
drop table #Shift 

CREATE TABLE #Shift(
    FKEmployeeNumber int, 
    DateOfBusiness datetime, 
    FKStoreId int, 
    EmployeeShiftNumber int, 
    FKJobCodeId int, 
    InHour int, 
    InMinute int, 
    OutHour int, 
    OutMinute int) 

insert into #Shift (FKEmployeeNumber, DateOfBusiness, FKStoreId, EmployeeShiftNumber, FKJobCodeId, InHour, InMinute,OutHour,OutMinute) 
values 
(529251, '11/13/2017', 3013, 0, 1, 8, 1, 16, 24), 
(529251, '11/14/2017', 3013, 0, 1, 15, 21, 23, 28), 
(529251, '11/15/2017', 3013, 0, 1, 8, 56, 15, 58), 
(529251, '11/16/2017', 3013, 0, 1, 14, 59, 20, 54), 
(529251, '11/19/2017', 3013, 0, 1, 12, 40, 19, 42), 
(529251, '11/20/2017', 3013, 1, 1, 8, 28, 23, 47), 
(529251, '11/21/2017', 3013, 0, 1, 15, 31, 23, 30), 
(529251, '11/25/2017', 3013, 0, 1, 10, 26, 18, 13), 
(529251, '11/27/2017', 3013, 0, 1, 9, 58, 18, 27), 
(529251, '11/28/2017', 3013, 0, 1, 14, 59, 2, 32), 
(529251, '11/29/2017', 3013, 0, 1, 10, 11, 17, 13), 
(529251, '11/29/2017', 3013, 1, 1, 17, 16, 17, 25), 
(529251, '11/30/2017', 3013, 0, 1, 15,4, 20, 0), 
(529251, '11/30/2017', 3013, 1, 1, 20, 0, 23, 18), 
(529251, '11/30/2017', 3013, 2, 1, 23, 18, 23, 22), 
(529251, '12/01/2017', 3013, 0, 1, 12, 12, 16, 0) 


;with cte as(
select 
    FKEmployeeNumber 
    ,DateOfBusiness 
    ,FKStoreId 
    ,EmployeeShiftNumber 
    ,FKJobCodeId 
    ,clockin = cast(convert(varchar(10),DateOfBusiness,101) + ' ' + right('00' + cast(InHour as varchar),2) + ':' + right('00' + cast(InMinute as varchar),2) as datetime) 
    ,clockout = cast(convert(varchar(10),DateOfBusiness,101) + ' ' + right('00' + cast(OutHour as varchar),2) + ':' + right('00' + cast(OutMinute as varchar),2) as datetime) 
from 
    #Shift), 

cte2 as(
select *, RN = row_number() over (partition by FKEmployeeNumber order by clockin) 
from cte) 

select 
    c.FKEmployeeNumber 
    ,c.DateOfBusiness 
    ,c.FKStoreId 
    ,c.EmployeeShiftNumber 
    ,c.FKJobCodeId 
    ,c.clockin 
    ,c.clockout 
    ,nexClockInHourDifference = datediff(minute,c.clockout,c2.clockin)/60.0 
from cte2 c 
left join cte2 c2 on c2.FKEmployeeNumber = c.FKEmployeeNumber and c2.RN = c.RN + 1 

drop table #Shift 

Auch da Sie auf 2012 sind, Sie LEAD hier verwenden können, und entfernen Sie die row_number() Funktion ....

;with cte as(
select 
    FKEmployeeNumber 
    ,DateOfBusiness 
    ,FKStoreId 
    ,EmployeeShiftNumber 
    ,FKJobCodeId 
    ,clockin = cast(convert(varchar(10),DateOfBusiness,101) + ' ' + right('00' + cast(InHour as varchar),2) + ':' + right('00' + cast(InMinute as varchar),2) as datetime) 
    ,clockout = cast(convert(varchar(10),DateOfBusiness,101) + ' ' + right('00' + cast(OutHour as varchar),2) + ':' + right('00' + cast(OutMinute as varchar),2) as datetime) 
from 
    #Shift) 


select 
    c.FKEmployeeNumber 
    ,c.DateOfBusiness 
    ,c.FKStoreId 
    ,c.EmployeeShiftNumber 
    ,c.FKJobCodeId 
    ,c.clockin 
    ,c.clockout 
    ,nexClockInHourDifference = datediff(minute,c.clockout,lead(c.clockin) over(partition by FKEmployeeNumber order by clockin))/60.0 
from cte c 

drop table #Shift