Wie werden alle Zeilen in einer Tabelle für alle Gruppen in einer anderen Tabelle wiederholt?

Question

Wie werden alle Zeilen in einer Tabelle für alle Gruppen in einer anderen Tabelle wiederholt?

Answer 1

dies versuchen,

SELECT d.*, dp.dept, u.users_created 
FROM dbo.dates d 
CROSS APPLY (SELECT DISTINCT dept FROM dbo.users) as dp 
OUTER APPLY (SELECT COUNT(*) users_created 
       FROM dbo.users u 
       WHERE u.dept = dp.dept 
       AND u.created_at >= d.month_start 
       AND u.created_at < d.next_month_start 
      ) as u 

Answer 2

Machen Sie einen einfachen SELECT COUNT von bestimmten Daten?

SELECT month_start, next_month_start, sum(cnt) as users, dept FROM 
(SELECT CASE WHEN created_at<=next_month_start AND created_at>=month_start THEN 1 ELSE 0 END as cnt, 
users.*, month_start, next_month_start FROM users 
CROSS JOIN dates) as S1 
GROUP BY dept, month_start, next_month_start ORDER BY dept DESC 

Answer 3

SELECT D.id dates_id,D.month_start dates_start,D.next_month_start dates_next_month_start,count(U.id) user_created,U.dept 

FROM dates D 
LEFT JOIN users U ON concat(year(U.created_at) ,"-",month(U.created_at)) = concat(year(D.month_start) ,"-",month(D.month_start)) 

GROUP BY concat(year(D.month_start) ,"-",month(D.month_start)) ,concat(year(D.next_month_start) ,"-",month(D.next_month_start)) ; 

Es folgt die aus

setzen

id month_start     next_month_start    user_created dept 
7 February, 01 2016 00:00:00 March, 01 2016 00:00:00  0    (null) 
6 March, 01 2016 00:00:00  April, 01 2016 00:00:00  2    sales 
5 April, 01 2016 00:00:00  May, 01 2016 00:00:00   3    sales 
4 May, 01 2016 00:00:00  June, 01 2016 00:00:00  0    (null) 
3 June, 01 2016 00:00:00  July, 01 2016 00:00:00  2    hr 
2 July, 01 2016 00:00:00  August, 01 2016 00:00:00  0    (null) 
1 August, 01 2016 00:00:00 September, 01 2016 00:00:00 0    (null) 

Answer 4

Haben Sie so etwas wie dieses brauchen?

SELECT sum(cnt), month_start, next_month_start, dept 
FROM 
(
    SELECT 
    CASE WHEN created_at<=next_month_start AND created_at>=month_start THEN 1 ELSE 0 END cnt, 
    users.*, month_start, next_month_start 
    FROM users 
    CROSS JOIN dates 
) sbt 
GROUP BY month_start, next_month_start, dept