Ich entwickle eine Website, in die ich Stripe-Payment-Gateway integrieren möchte. Ich implementiere diesen Code bereits auf einer anderen Website, aber dieser Code funktioniert nicht auf meiner aktuellen Website. Ich weiß nicht warum. Mein Code folgtVerhindern Stripe Form von Vorlage
-Code
<script type="text/javascript" src="https://js.stripe.com/v2/"></script>
<script type="text/javascript">
Stripe.setPublishableKey('API_KEY');
</script>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.2.0/jquery.min.js"></script>
<script>
$(document).ready(function(){
var $form = $('#paymentform');
$form.submit(function(event) {
event.preventDefault(event);
$form.find('#pay_submit').prop('disabled', true);
Stripe.card.createToken($form, stripeResponseHandler);
return false;
});
});
function stripeResponseHandler(status, response) {
var $form = $('#payment-form');
if (response.error) {
$form.find('.payment-errors').text(response.error.message);
$form.find('#pay_submit').prop('disabled', false);
} else {
var token = response.id;
$form.append($('<input type="hidden" name="stripeToken">').val(token));
$form.get(0).submit();
}
};
</script>
<form action="stripe.php" class="contact-form col-md-8 col-md-offset-2" method="POST" id="paymentform">
<span class="payment-errors"></span>
<label for="company-name">Company Name:</label>
<input type="text" class="form-control" id="company-name" name="company_name" required>
<label for="name">Your Name:</label>
<input type="text" class="form-control" id="name" name="name" required>
<label for="email">Email:</label>
<input type="email" class="form-control" id="email" name="email" required>
<label for="Phone">Phone:</label>
<input type="text" class="form-control" id="Phone" name="phone" required>
<label for="City">City:</label>
<input type="text" class="form-control" id="City" name="city" required>
<label for="stations">Address:</label>
<input type="text" class="form-control" id="stations" name="stations" required>
<label for="Card">Credit Card #:</label>
<input type="text" size="20" data-stripe="number" class="form-control" id="Card" required>
<label for="cvc">CVC:</label>
<input type="text" size="4" data-stripe="cvc" class="form-control" id="cvc" required>
<label for="exp_month">Expiry Month(MM):</label>
<input type="text" size="2" data-stripe="exp_month" class="form-control" id="exp_month" required>
<label for="exp_year">Expiry Year(YY):</label>
<input type="text" size="2" data-stripe="exp_year" class="form-control" id="exp_year" required>
<button type="submit" class="btn btn-default btn-lg getS-btn" id="pay_submit">PAY</button>
</form>
Andere Skripte am Ende der gleichen Seite, die ich für verschiedene Anwendungen sind
<script type="text/javascript" src="js/jquery.1.11.1.js"></script>
<script type="text/javascript" src="js/bootstrap.js"></script>
<script type="text/javascript" src="js/SmoothScroll.js"></script>
<script type="text/javascript" src="js/jquery.prettyPhoto.js"></script>
<script type="text/javascript" src="js/jquery.isotope.js"></script>
<script type="text/javascript" src="js/jqBootstrapValidation.js"></script>
<script type="text/javascript" src="js/contact_me.js"></script>
<script type="text/javascript" src="js/main.js"></script>
Ich denke, jquery nicht von der Form Vorlage verhindert, deshalb funktioniert api nicht.
Ja! Es gibt keinen Fehler auf der Konsole – Farhan