So speichern Sie Fremdschlüssel (SQL)

Question

$sql = "INSERT INTO deelnemer (Account_ID, BehaaldePunten, School_ID, Icon_ID) VALUES 
      ('Account_ID', (SELECT ID FROM account WHERE Gebruikersnaam = '$name'), 
      0, 
      ('School_ID', (SELECT ID FROM school WHERE Naam = '$school'), 
      ('Icon_ID', (SELECT ID FROM icon WHERE ID = 1)) 
      INNER JOIN account ON deelnemer.Account_ID = account.ID, 
      INNER JOIN school ON deelnemer.School_ID = school.ID"; 
      $result = $connection->prepare($sql); 
      $result->execute(); 

Hey Leute, ich bin ziemlich neu in SQL. Ich muss eine Zeile speichern, die einige Fremdschlüssel enthält, und ich habe schon einiges ausprobiert, aber nichts scheint zu funktionieren. Ich hoffe, Sie können mir helfen

xX

Dies ist die Fehlermeldung:

Fatal error: Uncaught exception 'PDOException' with message 'SQLSTATE[42000]: Syntax error or access violation: 1064 You have an error in your SQL syntax; check the manual that corresponds to your MariaDB server version for the right syntax to use near 'INNER JOIN account ON deelnemer.Account_ID = account.ID, INNER JO' at line 6' in C:\xampp\htdocs\GameBattle\test\Register_Modal.php:36 Stack trace: #0 C:\xampp\htdocs\GameBattle\test\Register_Modal.php(36): PDOStatement->execute() #1 C:\xampp\htdocs\GameBattle\test\login.php(84): require_once('C:\xampp\htdocs...') #2 {main} thrown in C:\xampp\htdocs\GameBattle\test\Register_Modal.php on line 36

Answer 1

Versuchen zu ersetzen:

('Account_ID', (SELECT ID FROM account WHERE Gebruikersnaam = '$name') 
      0, 
      ('School_ID', (SELECT ID FROM school WHERE Naam = '$school'), 

mit nur:

(SELECT ID FROM account WHERE Gebruikersnaam = '$name', 
      0, 
SELECT ID FROM school WHERE Naam = '$school' 
etc...)