PHP-Upload von iOS mit Alamofire

Question

Ich versuche, 3 Bilder auf den Server von iOS zu meinem PHP-Dienst hochladen. Aus irgendeinem Grund bleibt der Ordner nach der Veröffentlichung leer, aber der Rest der Daten wird durch und bleibt in mysql erhalten.

Mein iOS Code:

Alamofire.upload(.POST, urlString, multipartFormData: { 
      multipartFormData in 

      if (firstPhoto != nil) { 
       if let firstImageData = UIImageJPEGRepresentation(firstImage!, 0.6) { 
        print("uploading image"); 
        multipartFormData.appendBodyPart(data: firstImageData, name: "firstImage", fileName: "firstImage.png", mimeType: "image/png") 
       } 
      } 

      if (secondPhoto != nil) { 
       if let secondImageData = UIImageJPEGRepresentation(secondImage!, 0.6) { 
        print("uploading image"); 
        multipartFormData.appendBodyPart(data: secondImageData, name: "secondImage", fileName: "secondImage.png", mimeType: "image/png") 
       } 
      } 

      if (thirdPhoto != nil) { 
       if let thirdImageData = UIImageJPEGRepresentation(thirdImage!, 0.6) { 
        print("uploading image"); 
        multipartFormData.appendBodyPart(data: thirdImageData, name: "thirdImage", fileName: "thirdImage.png", mimeType: "image/png") 
       } 
      } 


      if let imageData = UIImageJPEGRepresentation(firstImage!, 0.6) { 
       print("uploading image"); 
       multipartFormData.appendBodyPart(data: imageData, name: "image", fileName: "file.png", mimeType: "image/png") 
      } 

      if let imageData = UIImageJPEGRepresentation(firstImage!, 0.6) { 
       print("uploading image"); 
       multipartFormData.appendBodyPart(data: imageData, name: "image", fileName: "file.png", mimeType: "image/png") 
      } 


      for (key, value) in parameters { 
       multipartFormData.appendBodyPart(data: value.dataUsingEncoding(NSUTF8StringEncoding)!, name: key) 
      } 

      }, encodingCompletion: { 
       encodingResult in 

       switch encodingResult { 
       case .Success(let upload, _, _): 
        print("Запрос отправлен") 
        upload.responseJSON { response in 
         print(response.request) // original URL request 
         print(response.response) // URL response 
         print(response.data)  // server data 
         print(response.result) // result of response serialization 

         if let JSON = response.result.value { 
          print("JSON: \(JSON)") 
         } 
         completion(response.result.value) 
        } 

       case .Failure(let encodingError): 
        print(encodingError) 
        completion(nil) 
       } 
     }) 

} 

Auf meinem PHP bin ich nicht sicher, ob ich etwas fehlt hier bin:

<?php 

require_once 'Functions/common_functions.php'; 
require_once 'Functions/engine.php'; 
require_once 'Functions/json.php'; 
require_once 'Functions/check_token.php'; 

if (count($_REQUEST) == 6) { 
    foreach($_REQUEST as $k => $v) { 
     if (strlen($k) > 0 && strlen($v) > 0) { 
      $_REQUEST[$mysqli->real_escape_string($k)] = $mysqli->real_escape_string($v); 
     } else { 
      die(errorJSON("Empty parameter", "666")); 
     } 
    } 

    $userID = checkAccessToken($_REQUEST['access_token'], $mysqli); 

    if ($userID == 0) { 
     die(errorJSON("Incorrect access token", "666")); 
    } 

    $mysqli->query('INSERT INTO Book (title, authorID, detail, price, categoryID, conditionText) VALUES ("'.$_REQUEST['title'].'", "'.$userID.'", "'.$_REQUEST['detail'].'", "'.$_REQUEST['price'].'", "'.$_REQUEST['categoryID'].'", "'.$_REQUEST['condition'].'")'); 

    $insertID = $mysqli->insert_id; 

    if ($insertID > 0) { 
     savePhotos($mysqli, $insertID); 
     $message = book($insertID, $userID, $mysqli); 
     die(successJSON($message)); 
    } else { 
     die(errorJSON("Failed insert book in database", "666")); 
    } 
} else { 
    die(errorJSON("Incorrect count of parameter" . count($REQUEST) . count($_POST), "666")); 
} 

function savePhotos($mysqli, $bookID) { 
    if(!is_dir('/home/thebakpa/resources/book_photos/')) { 
     mkdir('/home/thebakpa/resources/book_photos/', 0777, true); 
    } 
    try { 
     $uploaddir = '/home/thebakpa/resources/book_photos/'; 
     $file = $_FILES['userfile']['photo1']; 

     if ($file != 0) { 
      $uploadfile = $uploaddir . $file; 

      $name = "photo1-".$bookID; 
      $photoPath = '/home/thebakpa/resources/book_photos/'.$name.'.jpg'; 

      $mysqli->query('UPDATE Book SET photo1='.$photoPath.' WHERE bookID='.$bookID.''); 
      move_uploaded_file($_FILES['userfile']['tmp_name'], $uploadfile); 
     } 

     $file = $_FILES['userfile']['photo2']; 

     if ($file != 0) { 
      $uploadfile = $uploaddir . $file; 

      $name = "photo2-".$bookID; 
      $photoPath = '/home/thebakpa/resources/book_photos/'.$name.'.jpg'; 

      $mysqli->query('UPDATE Book SET photo1='.$photoPath.' WHERE bookID='.$bookID.''); 
      move_uploaded_file($_FILES['userfile']['tmp_name'], $uploadfile); 
     } 

     $file = $_FILES['userfile']['photo3']; 

     if ($file != 0) { 
      $uploadfile = $uploaddir . $file; 

      $name = "photo3-".$bookID; 
      $photoPath = '/home/thebakpa/resources/book_photos/'.$name.'.jpg'; 

      $mysqli->query('UPDATE Book SET photo1='.$photoPath.' WHERE bookID='.$bookID.''); 
      move_uploaded_file($_FILES['userfile']['tmp_name'], $uploadfile); 
     } 
    } catch(Exception $ex){ 
     echo "ERROR:".$ex->GetMessage()."\n"; 
     exit(1); 
    } 
} 
?> 

Answer 1

Problem ist in Ihrer savePhotos-Funktion von PHP-Quelle. Auch einige zusätzliche Code in iOS-Code geschrieben. Ich habe extra Code entfernt. Versuch es einmal.

ist der iOS-Code

Alamofire.upload(.POST, urlString, multipartFormData: { 
     multipartFormData in 

     if (firstPhoto != nil) { 
      if let firstImageData = UIImagePNGRepresentation(firstImage!, 0.6) { 
       print("uploading image"); 
       multipartFormData.appendBodyPart(data: firstImageData, name: "firstImage", fileName: "firstImage.png", mimeType: "image/png") 
      } 
     } 

     if (secondPhoto != nil) { 
      if let secondImageData = UIImagePNGRepresentation(secondImage!, 0.6) { 
       print("uploading image"); 
       multipartFormData.appendBodyPart(data: secondImageData, name: "secondImage", fileName: "secondImage.png", mimeType: "image/png") 
      } 
     } 

     if (thirdPhoto != nil) { 
      if let thirdImageData = UIImagePNGRepresentation(thirdImage!, 0.6) { 
       print("uploading image"); 
       multipartFormData.appendBodyPart(data: thirdImageData, name: "thirdImage", fileName: "thirdImage.png", mimeType: "image/png") 
      } 
     } 

     for (key, value) in parameters { 
      multipartFormData.appendBodyPart(data: value.dataUsingEncoding(NSUTF8StringEncoding)!, name: key) 
     } 

     }, encodingCompletion: { 
      encodingResult in 

      switch encodingResult { 
      case .Success(let upload, _, _): 
       print("Запрос отправлен") 
       upload.responseJSON { response in 
        print(response.request) // original URL request 
        print(response.response) // URL response 
        print(response.data)  // server data 
        print(response.result) // result of response serialization 

        if let JSON = response.result.value { 
         print("JSON: \(JSON)") 
        } 
        completion(response.result.value) 
       } 

      case .Failure(let encodingError): 
       print(encodingError) 
       completion(nil) 
      } 
    }) 

} 

aktualisiert und hier ist der Code PHP

function savePhotos($mysqli, $bookID) { 
    $basePath = '/home/thebakpa/resources/book_photos/' 
    if(!is_dir($basePath)) { 
     mkdir($basePath, 0777, true); 
    } 
    try { 
     $file1 = $_FILES['firstImage']; 

     if (is_uploaded_file($file1['tmp_name'])) { 
      $photoPath = $basePath.'photo1-'.$bookID.'.jpg'; 

      if (move_uploaded_file($file1['tmp_name'], $photoPath)) { 
       $mysqli->query('UPDATE Book SET photo1='.$photoPath.' WHERE bookID='.$bookID.''); 
      } 
     } 

     $file2 = $_FILES['secondImage']; 

     if (is_uploaded_file($file2['tmp_name'])) { 
      $photoPath = $basePath.'photo2-'.$bookID.'.jpg'; 

      if (move_uploaded_file($file2['tmp_name'], $photoPath)) { 
       $mysqli->query('UPDATE Book SET photo2='.$photoPath.' WHERE bookID='.$bookID.''); 
      } 
     } 

     $file3 = $_FILES['thirdImage']; 

     if (is_uploaded_file($file3['tmp_name'])) { 
      $photoPath = $basePath.'photo3-'.$bookID.'.jpg'; 

      if (move_uploaded_file($file3['tmp_name'], $photoPath)) { 
       $mysqli->query('UPDATE Book SET photo3='.$photoPath.' WHERE bookID='.$bookID.''); 
      } 
     } 
    } catch(Exception $ex){ 
     echo "ERROR:".$ex->GetMessage()."\n"; 
     exit(1); 
    } 
} 

Answer 2

Die Namen stimmen nicht überein ['userfile']['photo1'] in Ihrer PHP. Aber auf der iOS-Seite userfile und photo1 werden nie verwendet. Versuchen Sie mit $_FILES['firstImage']

Answer 3

dies versuchen, wenn Sie Bild im JSON-Format einreichen (für andere Bilder gleichen Code wiederholen, indem Sie Bildnamen chnaging)

<?php  

      $image   = $file; 
      $directorypath1 = $uploaddir; 
      $img   = str_replace('data:image/PNG;base64,', '', $image); 
      $img   = str_replace(' ', '+', $img); 
      $data   = base64_decode($img); 
      $name   = rand() . '_' . time() . ".jpg"; 
      $img_path  = $directorypath1 . $name; 
      file_put_contents($img_path, $data); 

?>