Warum diese Gruppe.wartet immer erfolgreich?

Question

Ich versuche, Timeout von group.wait zu bekommen, aber das ist immer erfolgreich.

blueGroup.enter() 
for i in 1...1000000 { 
    print(i) 
} 
blueGroup.leave() 

let time: DispatchTime = .now() + .seconds(1) 
let result = blueGroup.wait(timeout: time) 

print("finished \(result)") // always success 


let redGroup = DispatchGroup() 
redGroup.enter() 
for i in 0...300000 { 
    print(i/(i + 1)) 
    if i == 300000 { 
     print(i) 
     let result = redGroup.wait(timeout: .now() + .seconds(10)) 
     print(result) // always timeout 
     redGroup.leave() 
    } 
} 

Wo bin ich falsch?

danke

Answer 1

blueGroup.enter() // Now the Blue Group will block waiters 
for i in 1...1000000 { 
    print(i) 
} 
blueGroup.leave() // Blue group leaves match enters, so no blocking 

let time: DispatchTime = .now() + 0.001 
print(time)  
let result = blueGroup.wait(timeout: time) // Nothing blocking, so moving on 

print("finished \(result)") // finished success (as expected) 

Wenn Sie mit der Gruppe nicht fertig sind, kann es nicht lassen.