Ich versuche, das Wertattribut einer 5-Sterne-Bewertung zu bekommen, aber wenn ich darüber schwebe, werde ich undefiniert. Wenn ich attr ('Klasse') anstelle von attr ('Wert') habe, funktioniert es. Ich habe mich gefragt, ob mir jemand helfen könnte. Vielen Dank.Attr ('Wert') gibt zurück undefined
<fieldset class="rating">
<input type="radio" id="star5" name="rating" value="5" /><label class = "full" for="star5" title="Awesome - 5 stars"></label>
<input type="radio" id="star4half" name="rating" value="4 and a half" /><label class="half" for="star4half" title="Pretty good - 4.5 stars"></label>
<input type="radio" id="star4" name="rating" value="4" /><label class = "full" for="star4" title="Pretty good - 4 stars"></label>
<input type="radio" id="star3half" name="rating" value="3 and a half" /><label class="half" for="star3half" title="Meh - 3.5 stars"></label>
<input type="radio" id="star3" name="rating" value="3" /><label class = "full" for="star3" title="Meh - 3 stars"></label>
<input type="radio" id="star2half" name="rating" value="2 and a half" /><label class="half" for="star2half" title="Kinda bad - 2.5 stars"></label>
<input type="radio" id="star2" name="rating" value="2" /><label class = "full" for="star2" title="Kinda bad - 2 stars"></label>
<input type="radio" id="star1half" name="rating" value="1 and a half" /><label class="half" for="star1half" title="Meh - 1.5 stars"></label>
<input type="radio" id="star1" name="rating" value="1" /><label class = "full" for="star1" title="Sucks big time - 1 star"></label>
<input type="radio" id="starhalf" name="rating" value="half" /><label class="half" for="starhalf" title="Sucks big time - 0.5 stars"></label>
</fieldset>
Hier ist die Javascript
$(document).on('mouseover', '.rating', function(e) {
var c = $(e.target).attr('value')
alert(c);
});
es etwas aufmerksam tut, als ich versuchte, dass – srsxyz