Pass js Parameter Wert in der Datenbank mit PHP

Question

<input class="stars" type="radio" id="star5" onclick="myFunction('Overall rating:',5)" name="rating" value="5" /> 
<label class = "full" for="star5" title="Awesome - 5 stars"></label> 
<input class="stars" type="radio" id="star4" onclick="myFunction('Overall rating:',4)" name="rating" value="4" /> 
<label class = "full" for="star4" title="Pretty good - 4 stars"></label> 
<input class="stars" type="radio" id="star3" onclick="myFunction('Overall rating:',3)" name="rating" value="3" /> 
<label class = "full" for="star3" title="Meh - 3 stars"></label> 
<input class="stars" type="radio" id="star2" onclick="myFunction('Overall rating:',2)" name="rating" value="2" /> 
<label class = "full" for="star2" title="Kinda bad - 2 stars"></label> 
<input class="stars" type="radio" id="star1" onclick="myFunction('Overall rating:',1)" name="rating" value="1" /> 
<label class = "full" for="star1" title="Sucks big time - 1 star"></label> 
<font size="4"color="#ffffff">Overall rating:</font> 

Wie übergebe ich js Parameterwert in der Datenbank mit PHP?

Answer 1

von Ajax

myFunction (Yourstring, value) {

$ .get ('updatePage.php' { 'yourkeyString': Yourstring 'yourValue': Wert}, function (d) { alert ('Hallo von PHP:' + d); });

}

Kann diese Antwort auch prüfen https://stackoverflow.com/a/712378/6124249

Answer 2

Onchange() von Radiobutton eine Ajax-Funktion aufrufen, die Ihre Antwort in der Datenbank gespeichert werden.