Angenommen, ich habe Struktur als;
{
"class" : "TESTCLASS",
"id" : "HyvF1sdZl",
"depends" : [
"S11T5ce",
"BytQLN6ml",
"Byzz8Ea7l",
"r1TUNX58x"
],
"list" : [
{
"class" : "DATA",
"id" : "H113d5Pwx"
},
{
"class" : "DATA",
"id" : "H113d5Pwx"
},
{
"class" : "TEST",
"id" : "r1TUNX58x"
},
{
"class" : "DATA",
"id" : "H113d5Pwx"
},
{
"class" : "TEST",
"id" : "r1TUNX58x"
},
{
"class" : "TEST",
"id" : "r1TUNX58x"
},
{
"class" : "FDSAFAS",
"id" : "S11T5ce"
},
{
"class" : "YENITEST",
"id" : "r1TUNX58x"
},
{
"class" : "FDSAFAS",
"id" : "S11T5ce"
},
{
"class" : "CALENDAR",
"id" : "S11T5ce"
},
{
"class" : "EN",
"id" : "BytQLN6ml"
},
{
"class" : "CALENDAR",
"id" : "S11T5ce"
},
{
"class" : "EN_",
"id" : "Byzz8Ea7l"
},
{
"class" : "TEST",
"id" : "r1TUNX58x"
},
{
"class" : "EN",
"id" : "BytQLN6ml"
},
{
"class" : "FDSAFAS",
"id" : "S11T5ce"
}
]
}
Ich möchte project
list
Elemente, deren id
‚s sind in depends
Array enthalten.
Ich meine, ich will nur bekommen;
"depends" : [
"S11T5ce",
"BytQLN6ml",
"Byzz8Ea7l",
"r1TUNX58x"
],
"list" : [
{
"class" : "FDSAFAS",
"id" : "S11T5ce"
},
{
"class" : "EN",
"id" : "BytQLN6ml"
},
{
"class" : "EN_",
"id" : "Byzz8Ea7l"
},
{
"class" : "TEST",
"id" : "r1TUNX58x"
}
]
Um dies tun zu können, habe ich geschrieben;
db.definition.aggregate([
{
$project: {
_id: 0,
depends :1,
depends: {$in: ["$list.id"]},
"list.defid": 1,
"list.class" :1,
}
}
]).pretty()
Aber das wirft einen Fehler als "errmsg" : "Expression $in takes exactly 2 arguments. 1 were passed in."
Was bin ich?
In MongoDB 3.4 sollten Sie das ['$ in'] (https: //docs.mongodb.com/manual/reference/operator/aggregation/in /) aggregationsoperator anstelle von $ setIsSubset – styvane
@ M.StyvaneSoukossi In der Tat! Danke für den Zeiger – chridam