ich diese SQL-Abfrage erstellen möchten:Linq Left Outer Join mit dem Grafen
SELECT
a.[Seat],
b.[PlayerId],
b.[UserName],
b.[NickName],
COUNT(c.PlayerId) AS Trophy
FROM [dbo].[tbl_PlayerTableSeat] AS a
INNER JOIN [dbo].[tbl_Player] AS b ON a.[PlayerId] = b.[PlayerId]
INNER JOIN [dbo].[tbl_GameVirtualTable] AS d ON d.GameVirtualTableId = a.GameVirtualTableId
LEFT OUTER JOIN [dbo].[tbl_PlayerTableWinning] AS c ON a.[PlayerId] = c.[PlayerId] AND c.GameTableId = d.GameTableId
WHERE a.GameVirtualTableId = 36
GROUP BY a.[Seat], b.[PlayerId], b.[UserName], b.[NickName]
ich diese Linq haben
var virtualTableSeatList = (from s in db.PlayerTableSeat
join p in db.Player on s.PlayerId equals p.PlayerId
join v in db.GameVirtualTable on s.GameVirtualTableId equals v.GameVirtualTableId
join w in db.PlayerTableWinning on new { X1 = s.PlayerId, X2 = v.GameTableId } equals new { X1 = w.PlayerId, X2 = w.GameTableId } into gj
from g in gj.DefaultIfEmpty()
where s.GameVirtualTableId == virtualGameTableId
group new { p, s } by new { p.PlayerId, s.Seat, p.NickName, p.UserName } into grp
select new VirtualTableSeatDto
{
PlayerId = grp.Key.PlayerId,
Seat = grp.Key.Seat,
NickName = grp.Key.NickName,
UserName = grp.Key.UserName,
Trophy = grp.Count()
}
).ToList();
von SQL Profiler, die Linq diese SQL-Abfrage generiert:
exec sp_executesql N'SELECT
[GroupBy1].[K2] AS [PlayerId],
CAST([GroupBy1].[K1] AS int) AS [C1],
[GroupBy1].[K4] AS [NickName],
[GroupBy1].[K3] AS [UserName],
[GroupBy1].[A1] AS [C2]
FROM (SELECT
[Extent1].[Seat] AS [K1],
[Extent2].[PlayerId] AS [K2],
[Extent2].[UserName] AS [K3],
[Extent2].[NickName] AS [K4],
COUNT(1) AS [A1]
FROM [dbo].[tbl_PlayerTableSeat] AS [Extent1]
INNER JOIN [dbo].[tbl_Player] AS [Extent2] ON [Extent1].[PlayerId] = [Extent2].[PlayerId]
INNER JOIN [dbo].[tbl_GameVirtualTable] AS [Extent3] ON [Extent1].[GameVirtualTableId] = [Extent3].[GameVirtualTableId]
LEFT OUTER JOIN [dbo].[tbl_PlayerTableWinning] AS [Extent4] ON ([Extent1].[PlayerId] = [Extent4].[PlayerId]) AND ([Extent3].[GameTableId] = [Extent4].[GameTableId])
WHERE [Extent1].[GameVirtualTableId] = @p__linq__0
GROUP BY [Extent1].[Seat], [Extent2].[PlayerId], [Extent2].[UserName], [Extent2].[NickName]
) AS [GroupBy1]',N'@p__linq__0 int',@p__linq__0=36
Ich möchte COUNT(1) AS [A1]
zu COUNT([Extent4].[PlayerId]) AS [A1]
so kann es korrekte Daten zurückgeben. Ich habe keine Ahnung, wie die LinQ zu ändern
Trophy = grp.Count()
so dass es PlayerId
von PlayerTableWinning
statt COUNT zählen (1)
Aktualisiert: @Ivan Stoev
von Hinzufügen des g in die Gruppe.
group new { p, s, g }
und die Summe die Gruppe
Trophy = grp.Sum(item => item.w != null ? 1 : 0)
Es gibt die richtige Antwort. Es wird jedoch SUM statt Zählen verwendet. Die SQL-Abfrage erzeugt wird, wie unten:
exec sp_executesql N'SELECT
[GroupBy1].[K2] AS [PlayerId],
CAST([GroupBy1].[K1] AS int) AS [C1],
[GroupBy1].[K4] AS [NickName],
[GroupBy1].[K3] AS [UserName],
[GroupBy1].[A1] AS [C2]
FROM (SELECT
[Filter1].[K1] AS [K1],
[Filter1].[K2] AS [K2],
[Filter1].[K3] AS [K3],
[Filter1].[K4] AS [K4],
SUM([Filter1].[A1]) AS [A1]
FROM (SELECT
[Extent1].[Seat] AS [K1],
[Extent2].[PlayerId] AS [K2],
[Extent2].[UserName] AS [K3],
[Extent2].[NickName] AS [K4],
CASE WHEN (NOT (([Extent4].[GameTableId] IS NULL) AND ([Extent4].[PlayerId] IS NULL) AND ([Extent4].[GameRoundId] IS NULL))) THEN 1 ELSE 0 END AS [A1]
FROM [dbo].[tbl_PlayerTableSeat] AS [Extent1]
INNER JOIN [dbo].[tbl_Player] AS [Extent2] ON [Extent1].[PlayerId] = [Extent2].[PlayerId]
INNER JOIN [dbo].[tbl_GameVirtualTable] AS [Extent3] ON [Extent1].[GameVirtualTableId] = [Extent3].[GameVirtualTableId]
LEFT OUTER JOIN [dbo].[tbl_PlayerTableWinning] AS [Extent4] ON ([Extent1].[PlayerId] = [Extent4].[PlayerId]) AND ([Extent3].[GameTableId] = [Extent4].[GameTableId])
WHERE [Extent1].[GameVirtualTableId] = @p__linq__0
) AS [Filter1]
GROUP BY [K1], [K2], [K3], [K4]
) AS [GroupBy1]',N'@p__linq__0 int',@p__linq__0=36
Ist es nicht eigentlich das Gleiche? Auch in Ihrem sql - Sie zählen die 'playerId', aber eigentlich zählt nur die Anzahl der Datensätze in der Gruppe - es spielt also keine Rolle, ob es 1 ist oder die Spieler ID –
es ist nicht unterschiedlich zwischen count (1) und count (Spieler-ID). was willst du eigentlich? –
@EpoWilliam - Es sei denn, Sie möchten die genaue Menge von playerId wissen - ist das der Fall? –