dropzonejs senden für jedes Foto ein Ajax

Question

Ich möchte mehrere Dateien mit dropzone.js an den Server senden, wenn mein Formular eingereicht.

HTML und js

<form id="hotelDetails-entry" method="post" action="server/php/" enctype="multipart/form-data"> 

<div id="my-awesome-dropzone" class="dropzone dz-clickable"></div> 
... 
<input type="submit" name="submit" id="submit" value="save"/> 
</form> 

<script type="application/javascript"> 
$(document).ready(function() { 


    $('#hotel_name,#hotelNum').on('blur',function() { 
     var villaNum = $('#hotelNum').val().length; 
     var villaName = $('#hotel_name').val().length; 
     $('#submit').attr('disabled',true); 
     if((villaNum > 4) && (villaName > 0)){ 
      $('#submit').attr('disabled',false); 
     } 
    }); 

    Dropzone.options.myAwesomeDropzone = { 
     url: "server/php/", 
     paramName: "file", // The name that will be used to transfer the file 
     maxFilesize: 2, // MB 
     addRemoveLinks: true, 
     dictRemoveFile: 'حذف', 
     dictDefaultMessage: 'کلیک کنید', 
     autoProcessQueue: false, 
     parallelUploads : 10, 
     sending: function (file,xhr,formData) { 

     }, 
     init: function() { 
      myDropzone = this; 
      $('#hotelDetails-entry').on("submit", function() { 
       myDropzone.processQueue(); 
      }); 
     }, 
     success: function (file,res) { 

     }, 
     error: function (file,error,c) { 
      $('.error').html(error); 
     } 
    }; 
}); 

php

if (!empty($_FILES['file'])) { 

global $Core; 
global $mysqli; 
$upload = Upload::factory('image/hotel',$_SERVER['DOCUMENT_ROOT'] . "/hotel/");// upload herer 
$upload->file($_FILES['file']); 
//set max. file size (in mb) 
$upload->set_max_file_size(1); 

//set allowed mime types 
$upload->set_allowed_mime_types(array('image/jpeg')); 

$results = $upload->upload(); 

if($results['status'] == true){ 



     $inserHotel = $mysqli->query("INSERT INTO `hotels` (`hotelNum`, `hotel_name`, ..... 
     $vilId = mysqli_insert_id($inserHotel); 
     $mysqli->query("INSERT INTO `gallery` (`hotel_id`, `img`, `des`) VALUES ('". $vilId ."', '', NULL)"); 

    } 


} 

Wenn jedes Foto in die Tabelle eingefügt ein ro Weil für jedes Foto senden Sie eine Ajax-Anfrage.Wie alle Fotos in einer Anfrage an den Server zu senden.Ich möchte den Namen des Upload-Foto speichern, dass die Antwort von Upload.php zur Datenbank von Hotel_ID abhängen

Answer 1

ich finde es
nur
Dropzone.options.myAwesomeDropzone = { url: "testFile.php", paramName: "files", // The name that will be used to transfer the file maxFilesize: 2, // MB addRemoveLinks: true, dictRemoveFile: 'حذف', dictDefaultMessage: 'کلیک کنید', autoProcessQueue: false, parallelUploads : 10, uploadMultiple: true,<<<<<<<<<<<<<<<<<<<<<<<<<<<<this is problem sending: function (file,xhr,formData) {