search.phpPHP-Suche, aber zeigen Ergebnis in der nächsten Seite
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<!DOCTYPE html>
<html>
<head>
<style>
ul {
list-style-type: none;
margin: 0;
padding: 0;
overflow: hidden;
background-color: #333;
}
li {
float: left;
}
li a {
display: block;
color: white;
text-align: center;
padding: 14px 16px;
text-decoration: none;
}
li a:hover {
background-color: #111;
}
</style>
</head>
<body>
<?php
$query = $_GET['query'];
// gets value sent over search form
$min_length = 3;
// you can set minimum length of the query if you want
if(strlen($query) >= $min_length){ // if query length is more or equal minimum length then
$query = htmlspecialchars($query);
// changes characters used in html to their equivalents, for example: < to >
$query = mysql_real_escape_string($query);
// makes sure nobody uses SQL injection
$raw_results = mysql_query("SELECT * FROM register
WHERE (`Username` LIKE '%".$query."%') OR (`Firstname` LIKE '%".$query."%')") or die(mysql_error());
// * means that it selects all fields, you can also write: `id`, `title`, `text`
// articles is the name of our table
// '%$query%' is what we're looking for, % means anything, for example if $query is Hello
// it will match "hello", "Hello man", "gogohello", if you want exact match use `title`='$query'
// or if you want to match just full word so "gogohello" is out use '% $query %' ...OR ... '$query %' ... OR ... '% $query'
if(mysql_num_rows($raw_results) > 0){ // if one or more rows are returned do following
while($results = mysql_fetch_array($raw_results)){
// $results = mysql_fetch_array($raw_results) puts data from database into array, while it's valid it does the loop
echo "<p><h3>".$results['Username']."</h3>".$results['Contactnumber']."</p>";
// posts results gotten from database(title and text) you can also show id ($results['id'])
}
}
else{ // if there is no matching rows do following
echo "No results";
}
}
else{ // if query length is less than minimum
echo "Minimum length is ".$min_length;
}
?>
</body>
index.php
<!DOCTYPE html>
<html>
<head>
<style>
ul {
list-style-type: none;
margin: 0;
padding: 0;
overflow: hidden;
background-color: #333;
}
li {
float: left;
}
li a {
display: block;
color: white;
text-align: center;
padding: 14px 16px;
text-decoration: none;
}
li a:hover {
background-color: #111;
}
</style>
</head>
<body>
<body bgcolor="#919191">
<ul>
<li><a class="active" href="#home">Dashboard</a></li>
<li><a href="#news">Add Package</a></li>
<li><a href="#contact">View Customer</a></li>
<li><a href="#about">View Order</a></li>
</ul>
<form action="search.php" method="GET">
<input type="text" name="query" />
<input type="submit" value="Search" />
</form>
</body>
</html>
ist das möglich Show Ergebnis auf derselben Seite anstatt zu zeigen, auf Die nächste Seite? Da mein Ergebnis leer angezeigt wird, wollte ich auf meiner Seite zeigen, wer weiß wo das Problem zu beheben ist? Ich habe versucht hinzuzufügen, nicht zu helfen.
merge search.php Code in index.php wird das Problem –
vermeiden Verwendung von mysql function() lösen, da diese jetzt in PHP 7 –