2016-09-30 4 views
1

Ich bin mit der Simple do_POST Methodendatei zu erhalten. Das Skript funktioniert gut, wenn ich die PNG-Datei mit curl hochlade, aber jedes Mal, wenn ich die Python-Anforderungsbibliothek zum Hochladen der Datei verwende, werden Datei-Uploads aber korrupt. Hier ist der Code SimplePython Simple erhalten Dateien

#!/usr/bin/env python 
# Simple HTTP Server With Upload. 

import os 
import posixpath 
import BaseHTTPServer 
import urllib 
import cgi 
import shutil 
import mimetypes 
import re 
try: 
    from cStringIO import StringIO 
except ImportError: 
    from StringIO import StringIO 

class SimpleHTTPRequestHandler(BaseHTTPServer.BaseHTTPRequestHandler):  
    # Simple HTTP request handler with POST commands. 

    def do_POST(self): 
     """Serve a POST request.""" 
     r, info = self.deal_post_data() 
     print r, info, "by: ", self.client_address 
     f = StringIO() 

     if r: 
      f.write("<strong>Success:</strong>") 
     else: 
      f.write("<strong>Failed:</strong>") 

     length = f.tell() 
     f.seek(0) 
     self.send_response(200) 
     self.send_header("Content-type", "text/html") 
     self.send_header("Content-Length", str(length)) 
     self.end_headers() 
     if f: 
      self.copyfile(f, self.wfile) 
      f.close() 

    def deal_post_data(self): 
     print self.headers 
     boundary = self.headers.plisttext.split("=")[1] 
     print 'Boundary %s' %boundary 
     remainbytes = int(self.headers['content-length']) 
     print "Remain Bytes %s" %remainbytes 
     line = self.rfile.readline() 
     remainbytes -= len(line) 
     if not boundary in line: 
      return (False, "Content NOT begin with boundary") 
     line = self.rfile.readline() 
     remainbytes -= len(line) 
     fn = re.findall(r'Content-Disposition.*name="file"; filename="(.*)"', line) 
     if not fn: 
      return (False, "Can't find out file name...") 
     path = self.translate_path(self.path) 
     fn = os.path.join(path, fn[0]) 
     line = self.rfile.readline() 
     remainbytes -= len(line) 
     line = self.rfile.readline() 
     remainbytes -= len(line) 
     try: 
      out = open(fn, 'wb') 
     except IOError: 
      return (False, "Can't create file to write, do you have permission to write?") 

     preline = self.rfile.readline() 
     remainbytes -= len(preline) 
     while remainbytes > 0: 
      line = self.rfile.readline() 
      remainbytes -= len(line) 
      if boundary in line: 
       preline = preline[0:-1] 
       if preline.endswith('\r'): 
        preline = preline[0:-1] 
       out.write(preline) 
       out.close() 
       return (True, "File '%s' upload success!" % fn) 
      else: 
       out.write(preline) 
       preline = line 
     return (False, "Unexpect Ends of data.") 



    def translate_path(self, path): 
     """Translate a /-separated PATH to the local filename syntax. 

     Components that mean special things to the local file system 
     (e.g. drive or directory names) are ignored. (XXX They should 
     probably be diagnosed.) 

     """ 
     # abandon query parameters 
     path = path.split('?',1)[0] 
     path = path.split('#',1)[0] 
     path = posixpath.normpath(urllib.unquote(path)) 
     words = path.split('/') 
     words = filter(None, words) 
     path = os.getcwd() 
     for word in words: 
      drive, word = os.path.splitdrive(word) 
      head, word = os.path.split(word) 
      if word in (os.curdir, os.pardir): continue 
      path = os.path.join(path, word) 
     return path 

    def copyfile(self, source, outputfile): 
     """Copy all data between two file objects. 

     The SOURCE argument is a file object open for reading 
     (or anything with a read() method) and the DESTINATION 
     argument is a file object open for writing (or 
     anything with a write() method). 

     The only reason for overriding this would be to change 
     the block size or perhaps to replace newlines by CRLF 
     -- note however that this the default server uses this 
     to copy binary data as well. 

     """ 
     shutil.copyfileobj(source, outputfile) 



def test(HandlerClass = SimpleHTTPRequestHandler, 
     ServerClass = BaseHTTPServer.HTTPServer): 
    BaseHTTPServer.test(HandlerClass, ServerClass) 

if __name__ == '__main__': 
    test() 

Client-Seite Code, um eine Datei laden hier

#!/usr/bin/python 

import requests 

files = {'file': open('test.png', 'rb')} 
r = requests.post('http://192.168.5.134:8000', files=files) 
print r.request.headers 

Datei wurde erfolgreich hochgeladen aber beschädigt.

python request header

SimpleHTTPServer response

Mit curl [curl -F '[email protected]' 192.168.5.134:8000/ -v], Datei hochgeladen und erfolgreich geöffnet.

Gibt es eine Ausgabe in python-Anforderungs-Code?

Antwort

2

curl und request haben einen etwas anderen Header, curl hat eine zusätzliche leere Zeile, während requests nicht.

ersetzen preline = self.rfile.readline() mit dem folgenden Block

if line.strip(): 
    preline = line 
else: 
    preline = self.rfile.readline() 
+0

Amazing! :) Vielen Dank, Sir @Maximilan – john