PHP Instagram Freundschaften/create/Fehler

Question

Ich versuche, Freundschaften/erstellen/funktionieren in Instagram, aber ich habe einen Fehler.

Konto/Login-Funktion funktioniert.

Freundschaften/create Fehler: "Bitte aktualisieren Sie Ihre Instagram-App, um fortzufahren."

require_once("instagram.php"); 
$username = ''; 
$password = ''; 
$agent = 'Instagram 6.21.2 Android (19/4.4.2; 480dpi; 1152x1920; Meizu; MX4; mx4; mt6595; en_US)'; 
$guid = GenerateGuid(); 
$device_id = "android-".$guid; 
$data ='{"device_id":"'.$device_id.'","guid":"'.$guid.'","username":"'.$username.'","password":"'.$password.'","Content-Type":"application/x-www-form-urlencoded; charset=UTF-8"}'; 
$sig = GenerateSignature($data); 
$data = 'signed_body='.$sig.'.'.urlencode($data).'&ig_sig_key_version=6'; 
$login = SendRequest('accounts/login/', true, $data, $agent, false); 
print_r($login); 

/********** 

Login working successfully! No problem... 

***********/ 

/********* 
But error area is here. 
**********/ 

$device_id = "android-".$guid; 
$data = '{"device_id":"'.$device_id.'","guid":"'.$guid.'","device_timestamp":"'.time().'","Content-Type":"application/x-www-form-urlencoded; charset=UTF-8"}'; 
$sig   = GenerateSignature($data); 
$new_data  = 'signed_body='.$sig.'.'.urlencode($data).'&ig_sig_key_version=6'; 
$follow   = SendRequest('friendships/create/29180689', true, $new_data, $agent, true); 

=== === instagram.php

function SendRequest($url, $post, $post_data, $user_agent, $cookies) { 

$ch = curl_init(); 
curl_setopt($ch, CURLOPT_URL, 'https://instagram.com/api/v1/'.$url); 
/* 
curl_setopt($ch, CURLOPT_PROXY, $proxy); 
curl_setopt($ch, CURLOPT_PROXYUSERPWD, $proxyauth); 
*/ 
curl_setopt($ch, CURLOPT_USERAGENT, $user_agent); 
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true); 
curl_setopt($ch, CURLOPT_FOLLOWLOCATION, true); 

if($post) { 
    curl_setopt($ch, CURLOPT_POST, true); 
    curl_setopt($ch, CURLOPT_POSTFIELDS, $post_data); 
} 

if($cookies) { 
    curl_setopt($ch, CURLOPT_COOKIEFILE, 'cookies.txt');    
} else { 
    curl_setopt($ch, CURLOPT_COOKIEJAR, 'cookies.txt'); 
} 

$response = curl_exec($ch); 
$http = curl_getinfo($ch, CURLINFO_HTTP_CODE); 
curl_close($ch); 
return array($http, $response); 
} 
function GenerateGuid() { 
return sprintf('%04x%04x-%04x-%04x-%04x-%04x%04x%04x', 
     mt_rand(0, 65535), 
     mt_rand(0, 65535), 
     mt_rand(0, 65535), 
     mt_rand(16384, 20479), 
     mt_rand(32768, 49151), 
     mt_rand(0, 65535), 
     mt_rand(0, 65535), 
     mt_rand(0, 65535)); 
} 
function GenerateSignature($data) { 
return hash_hmac('sha256', $data, '25eace5393646842f0d0c3fb2ac7d3cfa15c052436ee86b5406a8433f54d24a5'); 
} 

Answer 1

Sie versuchen private APIs zu verwenden, die nicht von Instagram der Nutzungsbedingungen, so dass nur Menschen, die dort arbeiten erlaubt ist, wussten, was fehlt hier.

sind es öffentliche APIs, die erreichen können, was Sie hier tun wollte: https://instagram.com/developer/endpoints/relationships/#post_relationship

Answer 2

Ändern Sie diese Zeile:

$data = '{"device_id":"'.$device_id.'","guid":"'.$guid.'","device_timestamp":"'.time().'","Content-Type":"application/x-www-form-urlencoded; charset=UTF-8"}'; 

$data = '{"user_id":"'.$user_id.'","device_id":"'.$device_id.'","guid":"'.$guid.'","device_timestamp":"'.time().'","Content-Type":"application/x-www-form-urlencoded; charset=UTF-8"}'; 

Sie die user_id verpasst werden Parameter innerhalb der Anfrage.