join nicht in CakePHP Arbeits 3

Question

ich in controller diesen Code bin mit verbundenem Ergebnis zu erhalten, anstatt in CakePHP 3,2

$abc = $this->Products->SellerProducts->find('all', [ 
      'conditions' => [ 
      'Products.subcategory_id' => $id, 
      'SellerProducts.stock >' => 0, 
      ], 
      'join' => [ 
      'products' => [ 
       'table' => 'Products', 
       'type' => 'INNER', 
       'conditions' => [ 
       'products.id = SellerProducts.product_id' 
       ] 
      ], 
      'brands' => [ 
       'table' => 'Brands', 
       'type' => 'INNER', 
       'conditions' => 'brands.id = products.brand_id' 
      ], 
      'product_colors' => [ 
       'table' => 'ProductColors', 
       'type' => 'INNER', 
       'conditions' => 'product_colors.product_id = products.id' 
      ], 
      'colors' => [ 
       'table' => 'Colors', 
       'type' => 'INNER', 
       'conditions' => 'colors.id = product_colors.color_id' 
      ] 
      ] 
     ]); 

Aber auf debug assoziiert enthält, gibt es nur Daten aus SellerProducts und schließt nicht (beitreten) anderen Tabellen.

Ich möchte Ergebnis verbunden und nicht zugeordnetes Ergebnis mit contain Methode, weil contain gibt Multilevel-Array, die Sammlung von verknüpften Daten aus Multilevel-Array ist schwierig.

Edit 2: Ergebnis des Debug ($ abc);

SELECT SellerProducts.id AS `SellerProducts__id`, SellerProducts.seller_id AS `SellerProducts__seller_id`, SellerProducts.product_id AS `SellerProducts__product_id`, SellerProducts.selling_price AS `SellerProducts__selling_price` FROM seller_products SellerProducts INNER JOIN Products products ON products.id = SellerProducts.product_id INNER JOIN Brands brands ON brands.id = products.brand_id INNER JOIN ProductColors product_colors ON product_colors.product_id = products.id INNER JOIN Colors colors ON colors.id = product_colors.color_id WHERE (Products.subcategory_id = :c0 AND SellerProducts.stock > :c1) 

Answer 1

Ich glaube, Sie wie dies für alle Felder schreiben kann:

$this->SellerProducts->find('all',['fields' => [], 'conditions' => []] 

ODER

$this->SellerProducts->find('all', [ 
     'conditions' => [ 
     'Products.subcategory_id' => $id, 
     'SellerProducts.stock >' => 0, 
     ]])->join(.....); 

See Cakephp 3 join

Answer 2

Versuchen Sie, diese

$SellerProducts = TableRegistry::get('SellerProducts'); 
$resultSet = $SellerProducts->find('all')->hydrate(false) 
        ->select(['SellerProducts.id'])       
        ->join([ 
         'Products'=> [ 
          'table'  => 'products', 
          'type'  => 'INNER', 
          'conditions' => 'Products.id = SellerProducts.product_id', 
         ], 
         'Brands'=> [ 
          'table'  => 'brands', 
          'type'  => 'INNER', 
          'conditions' => 'Brands.id = Products.brand_id', 
         ], 
         'ProductColors'=> [ 
          'table'  => 'product_colors', 
          'type'  => 'INNER', 
          'conditions' => 'ProductColors.product_id = Products.id', 
         ], 
         'Colors'=> [ 
          'table'  => 'colors', 
          'type'  => 'INNER', 
          'conditions' => 'Colors.id = ProductColors.color_id', 
         ] 
        ]) 
        ->where([ 
         'Products.subcategory_id' => $id, 
         'SellerProducts.stock >' => 0 
        ]) 
        ->toArray(); 
    print_r($resultSet);