2017-06-29 5 views
-1

ich meine Web-Anwendung in IBM WebSphere Application Server Freiheit 17.0.0.2 eingesetzt und wenn ich versuche, es folgende Fehler bekommen zuzugreifen:meine Web-Anwendung Bereitstellen in IBM WebSphere Application Server Freiheit 17.0.0.2 erhöhen Fehler

Error Message: javax.servlet.ServletException: 
java.lang.NoClassDefFoundError: Could not initialize class 
com.x.y.z 
Error Code: 500 
Target Servlet: com.ibm.ws.webcontainer.extension.DefaultExtensionProcessor 
Error Stack: java.lang.NoClassDefFoundError: Could not initialize class com.x.y.z at 
com.ibm.ws.webcontainer.filter.FilterInstanceWrapper.doFilter(FilterInstanceWrapper.java:207) 
at com.ibm.ws.webcontainer.filter.WebAppFilterChain.doFilter(WebAppFilterChain.java:91) 
at com.ibm.ws.webcontainer.filter.WebAppFilterManager.doFilter(WebAppFilterManager.java:1021) 
at com.ibm.ws.webcontainer.filter.WebAppFilterManager.invokeFilters(WebAppFilterManager.java:1143) 
at com.ibm.ws.webcontainer.webapp.WebApp.handleRequest(WebApp.java:4983) 
at com.ibm.ws.webcontainer31.osgi.webapp.WebApp31.handleRequest(WebApp31.java:528) 
at com.ibm.ws.webcontainer.osgi.DynamicVirtualHost$2.handleRequest(DynamicVirtualHost.java:315) 
at com.ibm.ws.webcontainer.WebContainer.handleRequest(WebContainer.java:1025) 
at com.ibm.ws.webcontainer.osgi.DynamicVirtualHost$2.run(DynamicVirtualHost.java:280) 
at com.ibm.ws.http.dispatcher.internal.channel.HttpDispatcherLink$TaskWrapper.run(HttpDispatcherLink.java:967) 
at com.ibm.ws.http.dispatcher.internal.channel.HttpDispatcherLink.wrapHandlerAndExecute(HttpDispatcherLink.java:359) 
at com.ibm.ws.http.dispatcher.internal.channel.HttpDispatcherLink.ready(HttpDispatcherLink.java:318) 
at com.ibm.ws.http.channel.internal.inbound.HttpInboundLink.handleDiscrimination(HttpInboundLink.java:471) 
at com.ibm.ws.http.channel.internal.inbound.HttpInboundLink.handleNewRequest(HttpInboundLink.java:405) 
at com.ibm.ws.http.channel.internal.inbound.HttpInboundLink.processRequest(HttpInboundLink.java:285) 
at com.ibm.ws.http.channel.internal.inbound.HttpICLReadCallback.complete(HttpICLReadCallback.java:66) 
at com.ibm.ws.tcpchannel.internal.WorkQueueManager.requestComplete(WorkQueueManager.java:504) 
at com.ibm.ws.tcpchannel.internal.WorkQueueManager.attemptIO(WorkQueueManager.java:574) 
at com.ibm.ws.tcpchannel.internal.WorkQueueManager.workerRun(WorkQueueManager.java:929) 
at com.ibm.ws.tcpchannel.internal.WorkQueueManager$Worker.run(WorkQueueManager.java:1018) 
+0

I WebSphere Application Server Freiheit erstes Mal verwenden. Bitte geben Sie Ihren wertvollen Vorschlag –

+1

Was ist com.x.y.z und wie ist es verpackt? – covener

+0

@covener: Es ist ein Paket in unserer internen Anwendung. –

Antwort

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