Anzahl Datensätze für jeden Monat in einem Jahr

Question

I mit insgesamt keinen von 1000 Datensätze in it.It eine Tabelle haben die folgende Struktur:

EMP_ID EMP_NAME PHONE_NO ARR_DATE 
1  A  545454 2012/03/12 

Ich mag für jeden Monat im Jahres- keine Datensätze berechnen 2012

Gibt es irgendeine Möglichkeit, die mein Problem in einem einzigen Schuss lösen sollte?

Ich habe versucht:

select count(*) 
from table_emp 
where year(ARR_DATE) = '2012' and month(ARR_DATE) = '01' 

Answer 1

SELECT COUNT(*) 
FROM  table_emp 
WHERE  YEAR(ARR_DATE) = '2012' 
GROUP BY MONTH(ARR_DATE) 

Answer 2

select count(*) 
from table_emp 
where DATEPART(YEAR, ARR_DATE) = '2012' AND DATEPART(MONTH, ARR_DATE) = '01' 

Answer 3

Diese Abfrage:

SELECT 
    SUM(CASE datepart(month,ARR_DATE) WHEN 1 THEN 1 ELSE 0 END) AS 'January', 
    SUM(CASE datepart(month,ARR_DATE) WHEN 2 THEN 1 ELSE 0 END) AS 'February', 
    SUM(CASE datepart(month,ARR_DATE) WHEN 3 THEN 1 ELSE 0 END) AS 'March', 
    SUM(CASE datepart(month,ARR_DATE) WHEN 4 THEN 1 ELSE 0 END) AS 'April', 
    SUM(CASE datepart(month,ARR_DATE) WHEN 5 THEN 1 ELSE 0 END) AS 'May', 
    SUM(CASE datepart(month,ARR_DATE) WHEN 6 THEN 1 ELSE 0 END) AS 'June', 
    SUM(CASE datepart(month,ARR_DATE) WHEN 7 THEN 1 ELSE 0 END) AS 'July', 
    SUM(CASE datepart(month,ARR_DATE) WHEN 8 THEN 1 ELSE 0 END) AS 'August', 
    SUM(CASE datepart(month,ARR_DATE) WHEN 9 THEN 1 ELSE 0 END) AS 'September', 
    SUM(CASE datepart(month,ARR_DATE) WHEN 10 THEN 1 ELSE 0 END) AS 'October', 
    SUM(CASE datepart(month,ARR_DATE) WHEN 11 THEN 1 ELSE 0 END) AS 'November', 
    SUM(CASE datepart(month,ARR_DATE) WHEN 12 THEN 1 ELSE 0 END) AS 'December', 
    SUM(CASE datepart(year,ARR_DATE) WHEN 2012 THEN 1 ELSE 0 END) AS 'TOTAL' 
FROM 
    sometable 
WHERE 
    ARR_DATE BETWEEN '2012/01/01' AND '2012/12/31' 

Answer 4

Dies gibt Ihnen die Zählung pro Monat für das Jahr 2012;

SELECT MONTH(ARR_DATE) MONTH, COUNT(*) COUNT 
FROM table_emp 
WHERE YEAR(arr_date)=2012 
GROUP BY MONTH(ARR_DATE); 

Demo here.