mysql: Gruppe ergibt sich aus Anfragen

Question

My SQL-Anfrage gibt mir:

 SELECT 
     sf_guard_user.id, sf_guard_user.username, sf_guard_user.avatar_time, fromid, toid,sum(chatMessage.fromidlu) - sum(chatMessage.toidlu) as nonlus 
     FROM chatMessage, sf_guard_user 
     WHERE (chatMessage.fromid = sf_guard_user.id AND toid=16595 AND toidhidden=0) OR (chatMessage.toid = sf_guard_user.id AND fromid=16595 AND fromidhidden=0) 
     GROUP by fromid 

ich einen anderen SQL zu diesem Ergebnis so Endergebnis ist anwenden möchten macht die Summe auf 'nonlus'

SELECT id, username, avatar_time, fromid, toid, sum(nonlus) FROM 
**this request** 
order by id 

ich versuchte

SELECT id, username, avatar_time, fromid, toid, sum(nonlus) FROM (
      SELECT 
      sf_guard_user.id, sf_guard_user.username, sf_guard_user.avatar_time, fromid, toid,sum(chatMessage.fromidlu) - sum(chatMessage.toidlu) as nonlus 
      FROM chatMessage, sf_guard_user 
      WHERE (chatMessage.fromid = sf_guard_user.id AND toid=16595 AND toidhidden=0) OR (chatMessage.toid = sf_guard_user.id AND fromid=16595 AND fromidhidden=0) 
      GROUP by fromid) 
Group by id 

Aber Fehler

Jede abgeleitete Tabelle muss seinen eigenen alias

Answer 1

Sie müssen nur einen Alias ​​inneren select zuweisen, versuchen Sie haben die folgende erhalten:

SELECT id, username, avatar_time, fromid, toid, sum(nonlus) FROM (
      SELECT 
      sf_guard_user.id as id, sf_guard_user.username as username, sf_guard_user.avatar_time as avatar_time, fromid, toid, sum(chatMessage.fromidlu) - sum(chatMessage.toidlu) as nonlus 
      FROM chatMessage, sf_guard_user 
      WHERE (chatMessage.fromid = sf_guard_user.id AND toid=16595 AND toidhidden=0) OR (chatMessage.toid = sf_guard_user.id AND fromid=16595 AND fromidhidden=0) 
      GROUP by fromid) a 
Group by a.id