2017-05-30 4 views
-4

Gruppe von funktioniert nicht, kann sein, weil ich mathematischen Ausdruck in der Auswahloption verwende.Gruppe funktioniert nicht in Laravel 5.2

select FLOOR(SUM(DATEDIFF(rd.checkin_date,rd.created_at))/COUNT(DATEDIFF(rd.checkin_date,rd.created_at))) AS names, 
COUNT(rd.id) as totbooking, 
SUM(DATEDIFF(rd.checkout_date,rd.checkin_date)) AS nights, 
round(SUM(CASE WHEN h.currency_id=151 THEN rd.total_cents WHEN h.currency_id!=151 THEN rd.total_cents/cur.exchange_rate ELSE 0 END)/100) AS revenue, 
round((round(SUM(CASE WHEN h.currency_id=151 THEN rd.total_cents WHEN h.currency_id!=151 THEN rd.total_cents/cur.exchange_rate ELSE 0 END)/100))/(SUM(DATEDIFF(rd.checkout_date,rd.checkin_date)))) as adr, FLOOR((FLOOR(SUM(CASE WHEN h.currency_id=151 THEN rd.total_cents WHEN h.currency_id!=151 THEN rd.total_cents/cur.exchange_rate ELSE 0 END)/100))/COUNT(rd.id)) as atp, FLOOR(SUM(DATEDIFF(rd.checkin_date,rd.created_at))/COUNT(DATEDIFF(rd.checkin_date,rd.created_at))) as leadtime, 
SUM(DATEDIFF(rd.checkout_date,rd.checkin_date))/(COUNT(rd.id)) as alos, (SUM(DATEDIFF(rd.checkout_date,rd.checkin_date))/(h.total_rooms * 31))*100 as share from `reservation_details` as `rd` 
left join `hotels` as `h` on `rd`.`hotel_id` = `h`.`id` 
left join `currencies` as `cur` on `cur`.`id` = `h`.`currency_id` 
left join `chains` as `c` on `c`.`id` = `h`.`chain_id` 
where `rd`.`status` >= 50 and date(rd.created_at) >= "2017-04-30" and date(rd.created_at) <= "2017-05-30" GROUP BY names 
+1

Konnte Ihr Format das? Es ist unmöglich zu lesen – nacho

+1

Keine Fehler angezeigt? Ich nenne es dann arbeiten. – Chay22

+0

@nacho bitte überprüfen Sie jetzt –

Antwort

0

Warum don tun versuchen Sie es mit diesen Weg? Es würde helfen, wenn Sie uns einige Daten sehen lassen

select names,sum(totbooking),sum(nights),sum(revenue),sum(adr),leadtime,sum(alos),sum(share) 
from (
    select FLOOR(SUM(DATEDIFF(rd.checkin_date,rd.created_at))/COUNT(DATEDIFF(rd.checkin_date,rd.created_at))) AS names, COUNT(rd.id) as totbooking, 
    SUM(DATEDIFF(rd.checkout_date,rd.checkin_date)) AS nights,round(SUM(CASE WHEN h.currency_id=151 THEN rd.total_cents WHEN h.currency_id!=151 THEN rd.total_cents/cur.exchange_rate ELSE 0 END)/100) AS revenue, 
    round((round(SUM(CASE WHEN h.currency_id=151 THEN rd.total_cents WHEN h.currency_id!=151 THEN rd.total_cents/cur.exchange_rate ELSE 0 END)/100))/(SUM(DATEDIFF(rd.checkout_date,rd.checkin_date)))) as adr, FLOOR((FLOOR(SUM(CASE WHEN h.currency_id=151 THEN rd.total_cents WHEN h.currency_id!=151 THEN rd.total_cents/cur.exchange_rate ELSE 0 END)/100))/COUNT(rd.id)) as atp, FLOOR(SUM(DATEDIFF(rd.checkin_date,rd.created_at))/COUNT(DATEDIFF(rd.checkin_date,rd.created_at))) as leadtime, 
    SUM(DATEDIFF(rd.checkout_date,rd.checkin_date))/(COUNT(rd.id)) as alos, (SUM(DATEDIFF(rd.checkout_date,rd.checkin_date))/(h.total_rooms * 31))*100 as share 
    from `reservation_details` as `rd` 
    left join `hotels` as `h` on `rd`.`hotel_id` = `h`.`id` 
    left join `currencies` as `cur` on `cur`.`id` = `h`.`currency_id` 
    left join `chains` as `c` on `c`.`id` = `h`.`chain_id` 
    where `rd`.`status` >= 50 and date(rd.created_at) >= "2017-04-30" and date(rd.created_at) <= "2017-05-30") 
group by names 
+0

es einzelne Zeile zurück, aber ich möchte die Liste @nacho –

+0

@Rakesh Tripathi Es würde eine Menge helfen, wenn Sie einige Tabellen mit Daten hochladen, um zu sehen, was Sie brauchen – nacho

0

Sie alias verwenden, so in der GROUP BY Klausel Sie es verwenden sollte ich names nehme an, gehört zu hotels so müssen Sie es auf diese Weise

GROUP BY h.names 
+0

seine "Namen" bedeutet 'FLOOR (SUM (DATEDIFF (rd.checkin_date, rd.created_at))/COUNT (DATEDIFF (rd.checkin_date, rd.created_at))) AS Namen' –

+0

Sorry, ich habe es nicht gesehen – nacho

+0

Korrekt @ HoàngĐăng –

Verwandte Themen