mySQl Select-Abfrage zeigt keine erste Datenzeile an

Question

Die von mir erstellte MySQL-Abfrage zeigt keine erste Datenzeile an, aber der Rest ist in Ordnung. Dies ist Teil eines C++ Programms, das mySQL-Datenbank verbindet.

hier ist mein Code:

case 1: 
        cout << " You have selected the option 1" << endl; 


        MYSQL_RES *res_set1;       //Create a pointer to receive the return value 

        MYSQL_ROW row1;        //Assign variable for rows 

        sqlQuery1 = "select m.Name, ms.BoatName, o.LastName, o.FirstName, o.Address, o.City, o.State, o.Zip, ms.SlipNum from Marina m, MarinaSlip ms, Owner o where m.MarinaNum = ms.MarinaNum and ms.OwnerNum = o.OwnerNum"; 

        mysql_query(connect, sqlQuery1.c_str());  //Send a query to the database 

        res_set1 = mysql_store_result(connect);   //Receive the result and store it in res_set 


        //Check whether the result is empty 
        if ((row1 = mysql_fetch_row(res_set1)) == NULL) 
        { 
         cout << " There are no records in the Database."; 
         cout << endl; 
         goto menuOptions; 
        } 
        else 
        { 
         cout << endl; 
         cout << "|" << setfill(' ') << setw(21) << left << "Marina Name" << "|" << setw(16) << left << "Boat Name" << "|" << setw(17) << left << "Last Name" << "|" << setw(18) << left << "First Name" << "|" << setw(21) << left << "Address" << "|" << setw(14) << left << "City" << "|" << setw(11) << left << "State" << "|" << setw(9) << left << "Zip" << "|" << setw(9) << left << "SlipNum" << endl; 

         cout << "+" << setfill('-') << setw(19) << left << "-" << "+" << setw(16) << left << "-" << "+" << setw(15) << left << "-" << "+" << setw(18) << left << "-" << "+" << setw(20) << left << "-" << "+" << setw(15) << left << "-" << "+" << setw(12) << left << "-" << "+" << setw(10) << left << "-" << "+" << setw(10) << left << "-" << endl; 

         //This while is to print all rows 
         while ((row1 = mysql_fetch_row(res_set1)) != NULL) 
         { 

         cout << setfill(' ') << setw(22) << left << row1[0] << setw(17) << left << row1[1] << setw(17) << left << row1[2] << setw(18) << left << row1[3] << setw(21) << left << row1[4] << setw(19) << left << row1[5] << setw(12) << left << row1[6] <<setw(13) << left << row1[7] << setw(6) << left << row1[8] << endl; 
         cout << endl; 

         } 
        } 

        mysql_free_result(res_set1); 
        break; 

habe ich versucht, es herauszufinden, aber keine change..is es etwas falsch ich getan habe?

Dank

Answer 1

dieser Zeile:

if ((row1 = mysql_fetch_row(res_set1)) == NULL) 

die erste Zeile abruft. Aber du druckst es nicht aus. Sie verwenden es nur, um festzustellen, ob Sie Ergebnisse von Ihrer Abfrage erhalten haben. Und dann diese Zeile:

läuft die Schleife, wo Sie alle Zeilen beginnend mit Zeile # 2 drucken.