Konnte keine Verbindung zur Datenbank mit PHP und Mysql

Question

Ich habe ein Problem.Ich muss meine Datenbank verbinden und holen Sie den Wert der Tabelle.Aber es geschieht nicht so.Ich erkläre meinen Code unten.

index.php:

<?php 
session_start(); 
include_once 'dbcon/DBConnection.php'; 
$dbobj = new DBConnection(); 
$dbobj->connect(); 
if (isset($_REQUEST['msg'])){ 
    $msg = urlencode($_REQUEST['msg']); 
} 
if(isset($_POST["login"])){ 
    //echo 'hii';exit; 
    $loginid=htmlspecialchars(trim($_POST['txtname'])); 
    $password =sha1(htmlspecialchars(trim($_POST['pwd']))); 
    //echo $password;exit; 
    $admin = $dbobj->adminLogin($loginid,$password); 
    //echo ($admin->result);exit; 
    if($admin->result == 2){ 
     $msg ='2'; 
    } 
    if($admin->result ==1){ 
     $_SESSION["admin_id"] = $admin->adminid; 
     $_SESSION["admin_name"] = $admin->adminname; 
     $_SESSION["admin_loginid"] = $admin->adminloginid; 
     header("location:dashboard.php"); 
    } 
} 
?> 
<script> 
function valid() 
{ 
    var obj = document.frmlogin; 
    if(obj.txtname.value == "") 
    { 
     alert("Please Enter Username"); 
     obj.txtname.focus(); 
     return false; 
    } 
    if(obj.pwd.value == "") 
    { 
     alert("Please Enter Password"); 
     obj.pwd.focus(); 
     return false; 
    } 
    else 
    { 
     return true; 
    } 
} 
</script> 
<form method="post" name="frmlogin" id="frmlogin" action="" autocomplete="off" class="mt"> 
<label for="" class="text-uppercase text-sm">Username</label> 
<input type="text" placeholder="Username" name="txtname" class="form-control mb"> 
<label for="" class="text-uppercase text-sm">Password</label> 
<input type="password" placeholder="Password" name="pwd" class="form-control mb"> 
<div class="checkbox checkbox-circle checkbox-info"> 
<input id="checkbox7" type="checkbox" checked> 
<label for="checkbox7"> 
    Keep me signed in 
</label> 
</div> 

<button class="btn btn-primary btn-block" name="login" id="login" type="submit" onClick="return valid();">LOGIN</button> 

</form> 

DBConnection.php:

<?php 

class DBConnection{ 
    function __construct() { 

    } 
    // destructor 
    function __destruct() { 
     // $this->close(); 
    } 
    public function connect() { 
     require_once 'dbcon/config.php'; 
     $con = new mysqli(DB_HOST, DB_USER, DB_PASSWORD, DB_DATABASE);  
     if ($con->connect_error)die("Connection failed: "); 
     // return database handler 
     return $con; 
    } 
    public function adminLogin($loginid,$password){ 
     $admin = new AdminUser(); 
     if(ctype_alnum($loginid)){ 
      $sqllogin=sprintf("select * from ".PREFIX."admin where username='%s' and trim(password)='%s' and status=1",mysqli_real_escape_string($con,$loginid),mysqli_real_escape_string($con,$password)); 

      $dbsql=mysqli_query($con,$sqllogin); 

      $Num = mysqli_num_rows($dbsql); 
      echo $Num;exit; 
      if($Num >0){ 
       if($row=mysqli_fetch_array($dbsql)){ 
        $admin->adminid =htmlspecialchars($row['id']); 
        $admin->adminname =htmlspecialchars($row['name']); 
        $admin->adminloginid =htmlspecialchars($row['username']); 
        $admin->result=1; 
       } 
      }else{ 
       $admin->result=2; 
      } 
     }else{ 
      $admin->result=2; 
     } 
     return $admin; 
    } 
} 
?> 

Hier bin ich versucht, die Anzahl der Zeilen vorhanden, aber seine Anzeige nichts Echo. Bitte helfen Sie mir, dieses Problem zu lösen.

Answer 1

Als Grundlage der Reflexion, wenn Sie OOP verwenden, verwenden Sie es als OOP und nicht als Funktion libs.

begann ich etwas für Sie, können Sie es einfach so verwenden müssen:

$db = new DBConnection('host', 'user', 'pass', 'database_name'); 

$db->connect(); 

$data = $db->adminLogin('login', 'password'); 

-

class DBConnection 
{ 
    protected $_host = null; 
    protected $_user = null; 
    protected $_pass = null; 
    protected $_database = null; 

    protected $_con = null; 

    public function __construct($host, $user, $pass, $db) 
    { 
     $this->_host = $host; 
     $this->_user = $user; 
     $this->_pass = $pass; 
     $this->_database = $db; 
    } 

    function __destruct() 
    { 
     //$this->close(); 
    } 

    public function connect() 
    { 
     $con = new mysqli($this->_host, $this->_user, $this->_pass, $this->_database); 

     if ($con->connect_error) 
     { 
      die("Connection failed: "); 
     } 

     $this->_con = $con; 

     return $con; 
    } 
    public function adminLogin($login, $password) 
    { 
     $admin = new AdminUser(); 

     if(ctype_alnum($login)) 
     { 
      $sqllogin = sprintf(
       "select * from ".PREFIX."admin where username='%s' and trim(password)='%s' and status=1", 
       mysqli_real_escape_string($this->_con, $login), 
       mysqli_real_escape_string($this->_con, $password)); 

      $dbsql=mysqli_query($this->_con,$sqllogin); 

      $Num = mysqli_num_rows($dbsql); 
      echo $Num;exit; 
      if($Num >0){ 
       if($row=mysqli_fetch_array($dbsql)){ 
        $admin->adminid =htmlspecialchars($row['id']); 
        $admin->adminname =htmlspecialchars($row['name']); 
        $admin->adminloginid =htmlspecialchars($row['username']); 
        $admin->result=1; 
       } 
      }else{ 
       $admin->result=2; 
      } 
     }else{ 
      $admin->result=2; 
     } 
     return $admin; 
    } 
} 

Btw sehen über bitte prepare & bindParam & execute & get_result