Die beste Methode zum Abrufen der Kontaktliste

Question

Ich entwickle eine Kontakt-App mit drei Fragmenten (callLog, contactList, favoriteContactList). Wenn Sie eines zu einem anderen Fragment verschieben, benötigt es Zeit, alle Kontakte abzurufen. Ich habe ca. 276 Kontakte auf meinem Gerät. Jede Lösung, die Zeit reduziert.

ContentResolver cr = getContext().getContentResolver(); 
     String[] projection = {ContactsContract.Contacts._ID, 
       ContactsContract.Contacts.DISPLAY_NAME, 
       ContactsContract.Contacts.PHOTO_URI, 
       ContactsContract.Contacts.HAS_PHONE_NUMBER}; 

     Cursor cur = cr.query(ContactsContract.Contacts.CONTENT_URI, projection, null, null, ContactsContract.CommonDataKinds.Phone.DISPLAY_NAME + " ASC"); 
     String id, name, image_uri, phone = ""; 

     if (cur != null && cur.getCount() > 0) { 
      while (cur.moveToNext()) { 

       id = cur.getString(cur.getColumnIndex(ContactsContract.Contacts._ID)); 
       name = cur.getString(cur.getColumnIndex(ContactsContract.Contacts.DISPLAY_NAME)); 
       image_uri = cur.getString(cur.getColumnIndex(ContactsContract.CommonDataKinds.Phone.PHOTO_URI)); 

       Log.d(TAG, " name " + name + " id " + id); 

       // phone number 
       if (Integer.parseInt(cur.getString(cur.getColumnIndex(ContactsContract.Contacts.HAS_PHONE_NUMBER))) > 0) { 
        Cursor pCur = cr.query(ContactsContract.CommonDataKinds.Phone.CONTENT_URI, null, ContactsContract.CommonDataKinds.Phone.CONTACT_ID + " = ?", new String[]{id}, null); 
        if (pCur != null && pCur.moveToNext()) { 

         phone = pCur.getString(pCur.getColumnIndex(ContactsContract.CommonDataKinds.Phone.NUMBER)); 
         int colIndex = pCur.getColumnIndex(ContactsContract.CommonDataKinds.Phone.TYPE); 
         int lblIndex = pCur.getColumnIndex(ContactsContract.CommonDataKinds.Phone.LABEL); 
         int labelType = pCur.getInt(colIndex); 
         String phoneType; 

         if (labelType == ContactsContract.CommonDataKinds.Phone.TYPE_CUSTOM) { 
          phoneType = pCur.getString(colIndex); 
         } else { 
          phoneType = String.valueOf(ContactsContract.CommonDataKinds.Phone.getTypeLabel(this.getResources(), labelType, "Mobile")); 
         } 

         Log.d(TAG, phoneType + " " + phone); 
         pCur.close(); 
        } 
        mContactArrayList.add(new Contact(id, name, phone, image_uri)); 
       } 
      } 
      cur.close(); 
     } 

Answer 1

Versuchen Sie diesen Code

Cursor phones = getContentResolver().query(ContactsContract.CommonDataKinds.Phone.CONTENT_URI, null, null, null, null); 
    while (phones.moveToNext()) { 
     String name = phones.getString(phones.getColumnIndex(ContactsContract.CommonDataKinds.Phone.DISPLAY_NAME)); 
     String phone = phones.getString(phones.getColumnIndex(ContactsContract.CommonDataKinds.Phone.NUMBER)); 
     String id = phones.getString(phones.getColumnIndex(ContactsContract.CommonDataKinds.Phone.CONTACT_ID)); 
     String image_uri = phones.getString(phones.getColumnIndex(ContactsContract.CommonDataKinds.Phone.PHOTO_URI)); 

     mContactArrayList.add(new Contact(id, name, phone, image_uri)); 

    } 

Ich denke, es funktioniert.