Die Frage ist trivial, sobald die Daten normalisiert sind. Dies kann durch eine beliebige Anzahl von functions or tricks erfolgen.
Mit Microsoft Volltextsuche zur Verfügung:
With Src As (
Select * From (Values
(1, '10,11,12,13', 4),
(2, '10,13,15,4' , 5)
) V (Id, MentionedUserId, CreatorUserId)
), Normalised As (
Select CreatorUserId, CAST(display_term AS int) As MentionedUserId
From Src
Cross Apply (
Select display_term
From sys.dm_fts_parser('"' + MentionedUserId + '"', 1033, 0, 0)
Where display_term NOT Like 'nn%'
) Split
), UserList As (
Select CreatorUserId As UserId From Normalised Union
Select MentionedUserId From Normalised
)
Select UserId,
(Select Count(*) From Normalised Where MentionedUserId = UserId) As MentionedUserCount,
(Select Count(*) From Src Where CreatorUserId = UserId) As CreatorUserCount
From UserList;
Durch XML-Trick:
With Src As (
Select * From (Values
(1, '10,11,12,13', 4),
(2, '10,13,15,4' , 5)
) V (Id, MentionedUserId, CreatorUserId)
), Normalised As (
Select CreatorUserId, y.i.value('(./text())[1]', 'int') As MentionedUserId
From Src
Cross Apply (Select CONVERT(XML, '<i>' + REPLACE(MentionedUserId, ',', '</i><i>') + '</i>').query('.') As x) As a
Cross Apply x.nodes('i') As y(i)
), UserList As (
Select CreatorUserId As UserId From Normalised Union
Select MentionedUserId From Normalised
)
Select UserId,
(Select Count(*) From Normalised Where MentionedUserId = UserId) As MentionedUserCount,
(Select Count(*) From Src Where CreatorUserId = UserId) As CreatorUserCount
From UserList;
** Tipp: ** tun ** NICHT ** speichern mehrere Werte in einer einzigen Spalte - das ist ein schrecklich schlechtes Design ** und verletzt sogar die erste normale Form des Datenbankdesigns. Verwenden Sie geeignete relationale Konstrukte und speichern Sie * höchstens einen * Wert pro Spalte. –
Warum 'UserId'' 12' ist '0' in' MentionedUserCount'? –
Sorry, es sollte 1. Danke sein –