Echo Json-Array in einem phpMyAdmin Spalte VIA PHP

Question

Hallo Ich habe JSON Zeilen wie diese:

//THis is one of My Rows 
    [{"id":"26","answer":[{"option":"3","text":"HIGH"}],"type":"a"}, 
     {"id":"30","answer":[{"option":"3","text":"LOW"}],"type":"b"}, 
     {"id":"31","answer":[{"option":"3","text":"LOW"}],"type":"c"}, 
     {"id":"32","answer":[{"option":"3","text":"HIGH"}],"type":"d"}, 
     {"id":"33","answer":[{"option":"3","text":"HIGH"}],"type":"e"}, 
     {"id":"34","answer":[{"option":"3","text":"HIGH"}],"type":"f"}, 
     {"id":"40","answer":["Number 3"],"type":"g"}] 

Wie kann ich echo idanswertype,
und db Name: arrayTable Name: user_survey_startJSON row Name: survey_answers, Dies ist mein Code:

<?php 
    $con=mysqli_connect("localhost","root","","array"); 
    // Check connection 
    if (mysqli_connect_errno()) 
     { 
     echo "Failed to connect to MySQL: " . mysqli_connect_error(); 
     } 

    // $sql="SELECT survey_answers->"$.id" AS `twitter` FROM user_survey_start"; 
    $sql="SELECT survey_answers FROM user_survey_start"; 


    if ($result=mysqli_query($con,$sql)) 
     { 
     // Fetch one and one row 
     while ($row=mysqli_fetch_row($result)) 
     { 
     printf ("%s \n",$row[0]); 
     } 
     // Free result set 
     mysqli_free_result($result); 
    } 

    mysqli_close($con); 
    ?> 

Answer 1

Zuerst muss ich meinen Primärschlüssel auswählen

$sql="SELECT `survey_answers`,us_id FROM `user_survey_start`"; 

Dann Wert Put-ID In

$id[] = $data['id']; 

Danach

$sql1="update user_survey_start set id2='$ids' where us_id=".$row[1];//run update sql 
echo $sql1."<br>"; 

Answer 2

Sie können json_decode() Funktion verwenden, um Ihre json zu PHP-Array zu konvertieren(). Danach können Sie alle Daten als Ihre Anforderung durchlaufen.